To net_lover(孟子E章):
能不能给一点解释,我的javascript实在不够熟练。谢谢!
能不能给一点解释,我的javascript实在不够熟练。谢谢!
解决方案 »
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{
Result = null;
for (i=0; i<objRoot.length; i++)
{
if (objRoot[i].name==strName)
{
Result = obj[i];
break;
}
else
{
if (Result=searchTagWithName(objRoot[i],strName)) break;
}
}
return Result;
}
<TABLE id="moonpiazza" border="1">
<TR>
<TD>dsfds</TD>
<TD>dsf</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD>
<TABLE border="1">
<TR>
<TD><span>123</span></TD>
</TR>
</TABLE>
</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD><span>456</span></TD>
</TR>
</TABLE>
<INPUT TYPE="text" NAME="tagName" Id="tagName" value="span">
<INPUT TYPE="button" value="test" onclick="Test()">
<SCRIPT LANGUAGE="JavaScript">
<!--
function searchTagWithName(objRoot,strName)
{
var oItem = objRoot.getElementsByTagName(strName) ;
var n = oItem.length ;
if (n > 0)
{
return oItem[0];
}
else
{
return null;
}
}
function Test()
{
var sStr
var strName = tagName.value ;
if (strName == "")
strName = "span";
var oSrc = searchTagWithName(moonpiazza,strName);
if (oSrc == null)
{
sStr = "tagName:" + strName + " is null!"
}
else
{
sStr = "tagName:" + strName + "\n" ;
sStr += "innerHTML:" + oSrc.innerHTML ;
}
alert(sStr);
}//-->
</SCRIPT>
:_)
<TABLE id="moonpiazza" border="1">
<TR>
<TD>dsfds</TD>
<TD>dsf</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD>
<TABLE border="1">
<TR>
<TD><span name = "the target">123</span></TD>
</TR>
</TABLE>
</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD><span>456</span></TD>
</TR>
</TABLE>然后从table中找出name = "the target"的这个span。
function searchTagWithName(objRoot,strName){
return objRoot.getElementsByTagName(strName)?objRoot.getElementsByTagName(strName)[0]:null
}
</script>
function searchTagWithName(objRoot,strName){
return objRoot.all(strName)?objRoot.all(strName)[0].innerText:null
}
</script>
<TABLE id="moonpiazza" border="1">
<TR>
<TD>dsfds</TD>
<TD>dsf</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD>
<TABLE border="1">
<TR>
<TD><span id="the target">123</span><span id="the target">1223</span></TD>
</TR>
</TABLE>
</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD><span>456</span></TD>
</TR>
</TABLE><input type=button onclick="alert(searchTagWithName(moonpiazza,'the target'))">
1.不知道tag的名称(tagName)
2.只知道tag的属性name的值
3.获得属性name==strName的对象集合的第一个对象方法有2:
a.读取所有对象进行循环 searchTagWithName(objRoot,strName)
b.递归读取子节点 searchTagWithName02(objRoot,strName)
<TABLE id="moonpiazza" border="1">
<TR>
<TD>dsfds</TD>
<TD>dsf</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD>
<TABLE border="1">
<TR>
<TD><span name="the target">123</span></TD>
</TR>
</TABLE>
</TD>
</TR>
<TR>
<TD>dsfds</TD>
<TD><span name="test">456</span></TD>
</TR>
</TABLE>
<INPUT TYPE="text" NAME="cName" Id="cName" value="the target">
<INPUT TYPE="button" value="test" onclick="Test(cName.value)">
<BR>
<INPUT TYPE="text" NAME="cName2" Id="cName2" value="test">
<INPUT TYPE="button" value="test" onclick="Test(cName2.value)"><SCRIPT LANGUAGE="JavaScript">
<!--
function searchTagWithName(objRoot,strName)
{
// 读取所有对象进行循环
// 建议使用
var oChildNodes = objRoot.all ;
var n = oChildNodes.length ;
var i ;
var oRelust = null; for (i=0; i<n; i++)
{ if (oChildNodes[i].name == strName)
{
return oChildNodes[i] ;
}
}
}function searchTagWithName02(objRoot,strName)
{
// 递归读取子节点
var oChildNodes = objRoot.childNodes ;
var n = oChildNodes.length ;
var i ;
var oRelust = null; for (i=0; i<n; i++)
{ if (oChildNodes[i].name == strName)
{
return oChildNodes[i] ;
}
} for (i=0; i<n; i++)
{
oRelust = searchTagWithName(oChildNodes[i],strName);
if (oRelust != null)
{
return oRelust ;
}
} return oRelust ;
}
function Test(strName)
{
var sStr
if (strName == "")
strName = "span";
var oSrc = searchTagWithName(moonpiazza,strName);
if (oSrc == null)
{
sStr = "tag属性name:" + strName + " \n"
sStr += "this is null!" ;
}
else
{
sStr = "tag属性name:" + strName + "\n" ;
sStr += "innerHTML:" + oSrc.innerHTML ;
}
alert(sStr);
}
//-->
</SCRIPT>:_)