去掉数组中的重复值

Question

一个去除数组里重复元素例子
<%
 dim a,i,b(),j,tt
 redim preserve b(0)
 a = Array(1,2,1,3,3,4,5,5,6,7,2,2,9,8,9)
 for j = 0 to ubound(a)
   tt = 0
   for i = 0 to ubound(b)
     if b(i) = a(j) then tt = 1
   next
   if tt = 0 then
     redim preserve b(i+1)
     b(i+1) = a(j)
   end if
 next    '最后返回一个数组b()
%>

Answer 1

<script>
oldArray = [1,2,1,3,3,4,5,5,6,7,2,2,9,8,9]
var str = oldArray.join(" ");
var reg = /([^ ]+)(.*) \1/g;
while(str.match(reg))str=str.replace(reg,"$1$2")
alert(str.split(" "));
</script>

Answer 2

<script>
var tmp = new Array()
var a =new Array("AAAA","B","A","A","B","F","D","C","A","B","A","A","B","C")
tmp=a
for (var i=0;i<a.length;i++)
{
for(j=i+1;j<a.length;j++)
{
if(a[i]==a[j]) tmp[i]=null
}
}
var m = 0,ok = new Array()
for(k=0;k<tmp.length;k++)
{
if(tmp[k])
ok[m++] = tmp[k]
}
alert(ok)</script>

Answer 3

<script>
var a =new Array("AAAA","B","A","A","B","F","D","C","A","B","A","A","B","C")
for (var i=0;i<a.length;i++)
{
for(j=i+1;j<a.length;j++)
{
if(a[i]==a[j]) a[i]=null
}
}
var m = 0,ok = new Array()
for(k=0;k<a.length;k++)
{
if(a[k])ok[m++] = a[k]
}
alert(ok)
</script>

Answer 4

qiushuiwuhen(秋水无恨)的正则表达式真是用的拽呀Cool~~~~~

Answer 5

秋水的有Bug
Try:[1,2            2,1 1,2,3]

Answer 6

秋水的bug显然是分割符带来的,但是已经能够对付绝大多数情况了这样比遍历数组的速度肯定快些