<script>
function changeS1()
{//在php里循环 s2.options[i] = new Option("<?echo "xxxxx"?>")}</script>
function changeS1()
{//在php里循环 s2.options[i] = new Option("<?echo "xxxxx"?>")}</script>
调试欢乐多
function changeS2()
{
<?
$xxx=s1.value ;
$aa="select name from rszl where bumen='$xxx' ORDER by dm";
$rs1=mssql_query($aa,$comm);
$co=mssql_num_rows($rs1);
for ($i=0;$i<$co;$i++)
{
$re=@mssql_fetch_array($rs1);
?>
s2.options[i] = new Option("<? echo $re[name] ?>")
<? } ?>
}</script>==========================================================
我有两个options,s1和s2,当我选择s1时,就执行changeS2(),用php来读取s2的内容,以上是我写的function,不能成功执行,请问错在哪里?
or
s2.options[i] = new Option("<? echo $re["name"] ?>");