一个非常简单的，获得本机日期的问题

d.getUTCFullYear()d.getUTCFullMonth() + 1d.getUTCDate()

解决方案 »

  1.   

    给你个最完整的.这是前几天刚做完的
    <html>
    <body>
    <script>
    var dayarray=new Array("Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday")
    var montharray=new Array("January","February","March","April","May","June","July","August","September","October","November","December")function getthedate(){
    var mydate=new Date()
    var year=mydate.getUTCFullYear()
    if (year < 1000)
    year+=1900
    var day=mydate.getUTCDay()
    var month=mydate.getUTCMonth()
    var daym=mydate.getUTCDate()
    if (daym<10)
    daym="0"+daym
    var hours=mydate.getUTCHours()
    var minutes=mydate.getUTCMinutes()
    var seconds=mydate.getUTCSeconds()
    var dn="AM"
    if (hours>=12)
    dn="PM"
    if (hours>12){
    hours=hours-12
    }
    if (hours==0)
    hours=12
    if (minutes<=9)
    minutes="0"+minutes
    if (seconds<=9)
    seconds="0"+seconds
    //change font size here
    var Bj=8;
    //var Bjstr=parseInt(Bj);
    var cdate="<small><font color='000000' face='Arial'><b>"+dayarray[day]+", "+montharray[month]+" "+daym+", "+year+" "+hours+":"+minutes+":"+seconds+" "+dn
    var Bjdate="<small><font color='000000' face='Arial'><b>"+dayarray[day]+", "+montharray[month]+" "+daym+", "+year+" "+(hours+Bj)+":"+minutes+":"+seconds+" "+dn
    +"</b></font></small>"
    if (document.all){
    document.all.clock1.innerHTML=cdate;
    document.all.clock2.innerHTML=Bjdate;}
    //return(cdate);
    else
    document.write(cdate)
    }
    if (!document.all)
    getthedate()
    function goforit(){
    if (document.all)
    setInterval("getthedate()",1000)
    }</script>
    <font color='000000' face='Arial'><b>格林尼治时间：</b></font><span id="clock1"><script>goforit();</script></span><br>
    <font color='000000' face='Arial'><b>北京时间：</b></font><span id="clock2"><script>goforit();</script></span>
    </body>
    </html>