正则求助，请教大牛救急

Question

String str = "1,这里是数据\"data1 is here\",这里是数据2^hello.php?x1=11&x2=22,这里是数据2^bye.php?x3=33&x4=44,1,2,3省略";需要一个正则过滤^hello.php?x1=11&x2=22和^bye.php?x3=33&x4=44
对正则不大懂，请教大牛，想写一个过滤的"^*,"替换成","
请教大牛！求助！我写的最后结果成了 3,省略崩溃

Answer 1

rule
"\^[^,]+"
replace
""

Answer 2

what are you talking about?

Answer 3

过滤上面str中的^hello.php?x1=11&x2=22和^bye.php?x3=33&x4=44
从
"1,这里是数据\"data1 is here\",这里是数据2^hello.php?x1=11&x2=22,这里是数据2^bye.php?x3=33&x4=44,1,2,3省略";
得到
"1,这里是数据\"data1 is here\",这里是数据2,这里是数据,1,2,3省略";
这样的结果

Answer 4

var str="1,这里是数据\"data1 is here\",这里是数据2^hello.php?x1=11&x2=22,这里是数据2^bye.php?x3=33&x4=44,1,2,3省略";
str=str.replace(/\^\w+\.php\?(\w+=\w+&)*(\w+=\w+)?/g,"");
alert(str)

Answer 5

估计楼主是需要正则的非贪婪模式 <script type="text/javascript">
<!--
var str="1,这里是数据\"data1 is here\",这里是数据2^hello.php?x1=11&x2=22,这里是数据2^bye.php?x3=33&x4=44,1,2,3省略";
str=str.replace(/\^.*?,/g,",");
alert(str)
//-->
</script>

Answer 6

try...<script type="text/javascript"> 
var test = "1,这里是数据\"data1 is here\",这里是数据2^hello.php?x1=11&x2=22,这里是数据2^bye.php?x3=33&x4=44,1,2,3省略";
var reg = /\^[^^,]*/g;
var result = test.replace(reg, "");
document.write(result);
</script>