谁帮忙看看这个警告怎么解决？

Question

//Contents of SmEditor.js
var response = Ext.decode(Prometheus.DeviceRequestHelper.detect(request_id));  //contents of Sm.js
Ext.ns('myApp') 
myApp.DeviceRequestHelper = {  
    detect:function(request_id){  
        var task = function(){  
        Ext.Ajax.request({  
            url: 'device_requests.php',  
            params:{  
                action:'get_device', //in php  
                'request_id':request_id  
                },  
            timeout:30000, //30 seconds  
            success:function(response){//serverside response  
                var result = Ext.decode(response.responseText); //convert to js objects  
                if(result.success == true){//device was detected  
                    cons.log('success,device was detected');  
                    cons.log(result);  
                    Ext.TaskMgr.stop(runTask);  
                    return Ext.encode(result); //javascript strict warning  
                }else{  
                    if(runTask.taskRunCount >= 10){  
                        //retry limit exceeded  
                        Ext.Msg.show({  
                            title:'Server Failure',  
                            msg:"Detection Failed,Unable to detect device",  
                            icon: Ext.MessageBox.ERROR,  
                            buttons: Ext.Msg.OK  
                        });  
                        Ext.MessageBox.getDialog().getEl().setStyle('z-index','80000');  
                        Ext.TaskMgr.stop(runTask);  
                    }  
                }  
            },  
            failure:function(response){  
                Ext.TaskMgr.stop(runTask);  
                Ext.Msg.show({  
                    title:'Server Failure',  
                    msg:"Failed, server communication error",  
                    icon: Ext.MessageBox.ERROR,  
                    buttons: Ext.Msg.OK  
                });  
                Ext.MessageBox.getDialog().getEl().setStyle('z-index','80000');  
            }  
        })  
        }
        var runTask = {  
            run: task,  
            interval:2000,  
            repeat:10  
            };  
        Ext.TaskMgr.start(runTask);  
    }  
}    检测的时候总是出现warning:anonymous function does not always return a value. 这个警告，以至于我不能压缩JS代码？
请问怎么解决这个警告？？

Answer 1

这个是异步的 你在里边return无效 你最好在回调里用函数的方式将你的逻辑封装传入

Answer 2

你是这个意思吗？
function(callback){
 if(success)
   {
     return callback;
   }
}

Answer 3

//Contents of SmEditor.js
var response = Ext.decode(Prometheus.DeviceRequestHelper.detect(request_id,function(resault){ //这里就可以处理你的ajax函数中的callback参数了 传什么我们可以自己进行控制 也不会因为异步的问题出错
}));  //contents of Sm.js
Ext.ns('myApp') 
myApp.DeviceRequestHelper = {  
    detect:function(request_id,callback){  
        var task = function(){  
        Ext.Ajax.request({  
            url: 'device_requests.php',  
            params:{  
                action:'get_device', //in php  
                'request_id':request_id  
                },  
            timeout:30000, //30 seconds  
            success:function(response){//serverside response  
                var result = Ext.decode(response.responseText); //convert to js objects  
                if(result.success == true){//device was detected  
                    cons.log('success,device was detected');  
                    cons.log(result);  
                    Ext.TaskMgr.stop(runTask);  
                    
                }else{  
                    if(runTask.taskRunCount >= 10){  
                        //retry limit exceeded  
                        Ext.Msg.show({  
                            title:'Server Failure',  
                            msg:"Detection Failed,Unable to detect device",  
                            icon: Ext.MessageBox.ERROR,  
                            buttons: Ext.Msg.OK  
                        });  
                        Ext.MessageBox.getDialog().getEl().setStyle('z-index','80000');  
                        Ext.TaskMgr.stop(runTask);  
                    } 
                }
                callback(Ext.encode(result)); //这里增加回调  
            },  
            failure:function(response){  
                Ext.TaskMgr.stop(runTask);  
                Ext.Msg.show({  
                    title:'Server Failure',  
                    msg:"Failed, server communication error",  
                    icon: Ext.MessageBox.ERROR,  
                    buttons: Ext.Msg.OK  
                });  
                Ext.MessageBox.getDialog().getEl().setStyle('z-index','80000');  
            }  
        })  
        }
        var runTask = {  
            run: task,  
            interval:2000,  
            repeat:10  
            };  
        Ext.TaskMgr.start(runTask);  
    }  
}    

Answer 4

success:function(response){//serverside response    
                if(result.success == true){//device was detected    
                    return Ext.encode(result); //这里有return
                }else{  
                    这里没有return
                }  
            },  在一个函数里(success里)， 有的地方有return，有的地方没有return，所以会报那个warning1. 上面的return完全没有任何作用，可以去掉，就不会有warning了
2. 不知用的什么工具压缩，居然还会检查，那肯定有设置错误等级，设置忽略warning

Answer 5

即使有return 由于异步的原因也获取不到你return的变量值 所以最好的解决办法是写一个回调