karma(无为),但是在把图片放到多重表格中它的位置数值就很不准确了!有什么办法吗?

what do you mean? have you checked the positions? try this:
<body margin="0"><table cellspacing="0" cellpadding="0">
<tr>
<td>sss</td>
<td>
<table cellspacing="0" cellpadding="0">
<tr><td>sss</td>
<td><table cellspacing="0" cellpadding="0">
<tr>
<td>sss</td><td><img src="zip.gif"></td></tr>
</table></td>
</tr>
</table>
</td>
</tr>
</table><input type=button value="get" onclick="getPos()">
</body>
<script>
function getPos()
{
//alert(document.body.offsetTop);
for (var i=0; i < document.images.length;i++)
{
  var top=0, left=0;
  obj = document.images[i];
  while (obj && obj.tagName != "BODY")
  {
alert(obj.tagName +":" + obj.offsetLeft+":"+obj.offsetTop);
left += obj.offsetLeft;
top += obj.offsetTop;
obj = obj.parentElement;
  }
  //alert(obj.tagName);  alert(left + ":" +top);
}}
</script>

解决方案 »

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to verify the position, try to move the mouse around and look at the status bar:
<script language="javascript">
function document.onmousemove()
{
  window.status = event.clientX + "," + event.clientY;
}
</script>
多　karma(无为)兄,如果我在图片的上面回车，就得不多准确的top了.<table cellspacing="0" cellpadding="0" align="center">
  <tr>
    <td height="712">sss</td>
    <td height="712">
      <table cellspacing="0" cellpadding="0">
<tr>
          <td height="646">sss</td>
          <td height="646">
<table cellspacing="0" cellpadding="0">
<tr>
<td>sss</td>
                <td>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p> </p>
                  <p><img src="0001.gif" width="284" height="320" border="1"></p>
                </td>
              </tr>
</table></td>
</tr>
</table>
</td>
</tr>
</table>
function getPos()
{
//alert(document.body.offsetTop);
for (var i=0; i < document.images.length;i++)
{
  var top=0, left=0;
  obj = document.images[i];
  while (obj && obj.tagName != "BODY")
  {
if (obj.tagName != "P")
//alert(obj.tagName +":" + obj.offsetLeft+":"+obj.offsetTop);
{
left += obj.offsetLeft;
top += obj.offsetTop;
}
obj = obj.parentElement;
  }
  //alert(obj.tagName);  alert(left + ":" +top);
}}
karma(无为)，再请教，如何能使上面的代码在NETSCAPE中运行啊？谢谢你了
sorry, i do not know much about Netscape
试试把document去掉,也许还需要别的修改,没试过.