关于倒计时的问题

Question

function show_student163_time(date){
         window.setTimeout("show_student163_time("+date+")", 1000);
         BirthDay=new Date(date);//改成你的计时日期         today=new Date();
         timeold=(BirthDay.getTime()-today.getTime());
         sectimeold=timeold/1000
         secondsold=Math.floor(sectimeold);
         msPerDay=24*60*60*1000
         e_daysold=timeold/msPerDay
         daysold=Math.floor(e_daysold);
         e_hrsold=(e_daysold-daysold)*24;
         hrsold=Math.floor(e_hrsold);
         e_minsold=(e_hrsold-hrsold)*60;
         minsold=Math.floor((e_hrsold-hrsold)*60);
         seconds=Math.floor((e_minsold-minsold)*60);
         span_dt_dt.innerHTML=daysold+"天"+hrsold+"小时"+minsold+"分"+seconds+"秒" ;
         
        }
        show_student163_time(date);其中date只能是07-09-2011 12:0:0这种格式，如果我用2011-07-09 12:0:0则返回的是Nva天Nva小时Nva分Nva秒，请问如何才能在使用2011-07-09 12:0:0这种格式的时间能够实现倒计时

Answer 1

先把转时间转换一下不就行了吗?
可以用正则,或split

Answer 2

var ds = '07-09-2011 12:0:0';
var part = /(\d\d?)-(\d\d?)-(\d{4})\b(.{5,8})/;
ds = ds.replace(part,"$3-$1-$2 $4");