求一个能算出最近节日的JS方法，小女子谢谢了啊！

alert(sObj.innerHTML + '\r\n' + lObj.innerHTML);

还是哥来帮你吧<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>测试</title>
<script type="text/javascript">

</script>
</head>
<body>
<input type="button" value="测试" onclick="doIt();" />
</body>
</html>

哥，还是你了解我啊，知道我想要什么但是算法还有点问题啊0101有个节日
0201也有一个节日今天是0129，但是返回的还是0101的节日，好伤脑筋啊，好费脑子啊，我想了一会儿头就大了
妹子昨天那个没仔细看，这个应该没问题了：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>测试</title>
<script type="text/javascript">

</script>
</head>
<body>
<input type="button" value="测试" onclick="doIt();" />
</body>
</html>

上边的时间是我测试用的，改成当前时间吧 var D = new Date();

上边的时间是我测试用的，改成当前时间吧 var D = new Date();
不好意思，突然想到一个问题，就是如果V中的数据不是按顺序排列的话，结果就不对了。修改如下：var V = [
    {date: "1224", name : "平安夜"},
            {date: "0101", name: "元旦节"},
            {date: "0910", name : "中国教师节"},
            {date: "0214", name: "情人节"},
            {date: "0501", name : "劳动节"},
            {date: "0305", name: "学雷锋纪念日"},
            {date: "0308", name: "妇女节"},
            {date: "0312", name : "植树节"},
            {date: "0701", name : "中国GD诞辰"},
            {date: "0401", name : "愚人节"},
            {date: "0504", name : "青年节"},
            {date: "0601", name : "国际儿童节"},
            {date: "0801", name : "建军节"},
            {date: "1010", name : "国庆节"},
            {date: "1225", name : "圣诞节"},
            {date: "1111", name : "光棍节"}
        ];    V.sort(function(a,b){return a.date < b.date ? -1 : 1;});//按date大小升序排列
    // var D = new Date('2015/10/30');//获取指定日期的最近节日
    var D = new Date();
    var n = ('0' + (D.getMonth() + 1)).slice(-2) + ('0' + D.getDate()).slice(-2),k = 0;
    for(var i in V) n * 1 > V[i].date * 1 && k++;
    console.info('离当前日期最近的节日为：' + V.slice(k).shift().name);

听到楼主提到公历转农历，心生兴趣，特在网上查了下资料，最终将楼主需要的完整答案搞出来了
废话不多说了，完整代码如下：需要下载calendar.js<!DOCTYPE>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title></title>
<script type="text/javascript" src="calendar.js"></script>
<style>
</style>
</head>
<body>
    <div id="lunar"></div>
    <div id="solar"></div>
</body>
<script type='text/javascript'>
    var V =
    [//公历
        {date: "1224", name : "平安夜"},
        {date: "0101", name: "元旦节"},
        {date: "0910", name : "中国教师节"},
        {date: "0214", name: "情人节"},
        {date: "0501", name : "劳动节"},
        {date: "0305", name: "学雷锋纪念日"},
        {date: "0308", name: "妇女节"},
        {date: "0312", name : "植树节"},
        {date: "0701", name : "中国GD诞辰"},
        {date: "0401", name : "愚人节"},
        {date: "0504", name : "青年节"},
        {date: "0601", name : "国际儿童节"},
        {date: "0801", name : "建军节"},
        {date: "1010", name : "国庆节"},
        {date: "1225", name : "圣诞节"},
        {date: "1111", name : "光棍节"}
    ];
    var T =
    [//农历
        {date:"0101",name:"春节"},
        {date:"0115",name:"元宵节"},
        {date:"0505",name:"端午节"},
        {date:"0815",name:"中秋节"},
        {date:"0909",name:"重阳节"},
        {date:"1208",name:"腊八节"},
        {date:"1230",name:"除夕"}
    ]

    function recently(V,T){
        V = V || [],T = T || [],result = {};
        V.sort(function(a,b){return a.date < b.date ? -1 : 1;});//按date大小升序排列
        T.sort(function(a,b){return a.date < b.date ? -1 : 1;});//按date大小升序排列
        var D = new Date(),y = D.getFullYear(),m = D.getMonth() + 1,d = D.getDate();        //获取最近的公历节日
        var n = ('0' + m).slice(-2) + ('0' + d).slice(-2),k = 0;
        for(var i in V) n * 1 > V[i].date * 1 && k++;
        k = k >= V.length ? 0 : k;
        result.gl = V.slice(k).shift();

        //获取最近的农历节日
        var nl = calendar.lunar2solar(y,m,d);
        n = ('0' + nl.lMonth).slice(-2) + ('0' + nl.lDay).slice(-2),k = 0;
        for(var i in T) n * 1 > T[i].date * 1 && k++;
        k = k >= V.length ? 0 : k;
        result.nl = T.slice(k).shift();        return result;
    }
    var o = recently(V,T);
    document.getElementById('lunar').innerHTML = '离当前日期最近的节日(公历)：' + o.gl.name;
    document.getElementById('solar').innerHTML = '离当前日期最近的节日(农历)：' + o.nl.name;
</script>
</html>

调试易

求一个能算出最近节日的JS方法，小女子谢谢了啊！

解决方案 »