获取到的由后台返回的JSON数据如何解析使用？？？？？？？？？？？？

Question

jsonjavascript

Answer 1

$.ajaxFileUpload({
                type:'post',
                    url: 'tjttxx!upload.action', //用于文件上传的服务器端请求地址
                    secureuri: false, //是否需要安全协议，一般设置为false
                    fileElementId: 'uploadFile', //文件上传域的ID
                    //contentType: false, 
                    //processData: false,
                    dataType: 'JSON', //返回值类型 一般设置为json
                    success: function (value){  //服务器成功响应处理函数                                                         
                     var vData =eval('('+value+')')[0].data;                                                              
                      for(var i=0; i<vData.length; i++){   
                      var row = vData[i]; 
   $('#fzmc').datagrid('appendRow',{
 xm:row.xm,
                                         xb:row.xb,
                                      sfzhm:row.sfzhm,
                                       csny:row.csrq,                          
                                         dz:row.dz, 
                                         mz:row.mz,
                                       lxdh:row.lxdh,
                                         bm:row.bm,
                                         gh:row.gh,
                                         gl:row.gl                          
   });                   
  //                    $('#fzmc').datagrid('loadData', vData[0].data);                   
                   
                   }
                   },
                  error: function(data, status, e){
                     alert(e);
                   }  
          }) 我做了个和你差不多的 我是上传json 然后把它加到表格中