js遍历树结构

Question

我想遍历这样的数据，得到qx为1的节点，和这个节点的直接子节点，数据格式为这样
[
  {
    "thisNode": "10000480",
    "prientNode": "",
    "qx": "0",
    "children": [
      {
        "prientNode": "10000480",
        "thisNode": "10000470",
        "qx": "0",
        "children": []
      },
      {
        "prientNode": "10000480",
        "thisNode": "10000420",
        "children": [
          {
            "prientNode": "10000420",
            "thisNode": "10000551",
            "qx": "1",
            "children": [
              {
                "prientNode": "10000420",
                "thisNode": "10000551",
                "qx": "1",
                "children": []
              }
            ]
          }
        ]
      }
    ]
  }
]

Answer 1

    d = [{
        "thisNode": "10000480",
        "prientNode": "",
        "qx": "0",
        "children": [
          {
              "prientNode": "10000480",
              "thisNode": "10000470",
              "qx": "0",
              "children": []
          },
          {
              "prientNode": "10000480",
              "thisNode": "10000420",
              "children": [
                {
                    "prientNode": "10000420",
                    "thisNode": "10000551",
                    "qx": "1",
                    "children": [
                      {
                          "prientNode": "10000420",
                          "thisNode": "10000551",
                          "qx": "1",
                          "children": []
                      }
                    ]
                }
              ]
          }
        ]
    }
    ];
    function findChildren(arr, key, value,callback) {
        for (var i = 0; i < arr.length; i++) {
            if (arr[i][key] == value) callback(arr[i].children)
            findChildren(arr[i].children, key, value, callback);
        }
    }
    findChildren(d, 'qx', '1', function (children) {
        console.log(children)
    });Web开发学习资料推荐
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