怎么确定循环的次数

Question

现在有8项，设为固定8次循环时效果能实现，想改成循环次数根据item的多少来变动，而不是确定的一个数，或者如何改能更好的控制？
<script language="javascript">
 function turnit(obj_name)
 { 
  var ss=document.getElementById(obj_name);
var dd="item";
   if (ss.className=="none") 
{
for(i=1;i<=8;i++)
{
if(dd+i=="")
{}
else
{
document.getElementById("item"+ i).className="none";
}
}
ss.className="nomorl";
   }
   else
{
ss.className="none";
}
  }
</script>
                  <!--头部-->
                         <div class="menu1" onclick="turnit('item1')"><a href="#">内科</a></div>
                            <ul class="nomorl" id="item1">
                                <li><a href="#" target="_self">呼吸内科</a></li>
                                <li><a href="#" target="_self">心血管内科</a></li>
                                <li><a href="#" target="_self">消化内科</a></li>
                                <li><a href="#" target="_self">肾内科</a></li>
                                <li><a href="#" target="_self">神经内科</a></li>
                                <li><a href="#" target="_self">内分泌科</a></li>
                                <li><a href="#" target="_self">血液科</a></li>
                                <li><a href="#" target="_self">风湿内科</a></li>
                            </ul>
<div class="clear"></div>
                        <!--四肢--> 
                            <div class="menu1" onclick="turnit('item2')"><a href="#">外科</a></div>
                            <ul class="none" id="item2">
                                <li><a href="#" target="_self">上肢</a></li>
                                <li><a href="#" target="_self">下肢</a></li>
                            </ul>
                            
                            <div class="menu1" onclick="turnit('item3')"><a href="#">肿瘤科</a></div>
                            <ul class="none" id="item3">
                                <li><a href="#" target="_self">上肢</a></li>
                                <li><a href="#" target="_self">下肢</a></li>
                            </ul>
                            
                            <div class="menu1" onclick="turnit('item4')"><a href="#">男科</a></div>
                            <ul class="none" id="item4">
                                <li><a href="#" target="_self">上肢</a></li>
                                <li><a href="#" target="_self">下肢</a></li>
                            </ul>
                            
                            <div class="menu1" onclick="turnit('item5')"><a href="#">妇科</a></div>
                            <ul class="none" id="item5">
                                <li><a href="#" target="_self">上肢</a></li>
                                <li><a href="#" target="_self">下肢</a></li>
                            </ul>
                            
                            <div class="menu1" onclick="turnit('item6')"><a href="#">儿科</a></div>
                            <ul class="none" id="item6">
                                <li><a href="#" target="_self">上肢</a></li>
                                <li><a href="#" target="_self">下肢</a></li>
                            </ul>
                            
                            <div class="menu1" onclick="turnit('item7')"><a href="#">五官科</a></div>
                            <ul class="none" id="item7">
                                <li><a href="#" target="_self">上肢</a></li>
                                <li><a href="#" target="_self">下肢</a></li>
                            </ul>
                            
                            <div class="menu1" onclick="turnit('item8')"><a href="#">传染科</a></div>
                            <ul class="none" id="item8">
                                <li><a href="#" target="_self">上肢</a></li>
                                <li><a href="#" target="_self">下肢</a></li>
                            </ul>
                    

Answer 1

可以获得所有的DIV，然后判断id属性，indexOf(item)  大于0就执行操作

Answer 2

var nodes=document.getElementsByTagName("UL");
alert(nodes.length);nodes.length就是你要循环的次数

Answer 3

var allUl=document.getELementsByTagName("UL");
for(i=1;i<=allUl.length;i++){
if(allUl[i].id.indexOf("item")<0)
continue;
allUl[i].className="none";
}
for那里的代码改这样

Answer 4

不止这个地方有UL啊，其它地方也有，所以要根据ID判断，就是不知道怎么判断

Answer 5

LZ可以在最外边套一层Div 
<div id="outer">
   <!-- 你的html代码 ...-->
       
</div>
判断item的多少的js代码
document.getElementById('outer').getElementsByTagName('ul').length

Answer 6

6楼的方法或者用下面的方式例如：
<div id="test">
<ul>
只取id="test"的div嵌套的所有ul
</ul>
</div>那么可以这样document.getElementById("test").getElementsByTagName("ul")

Answer 7

<script language="javascript">

   function turnit(obj_name)
   { 
  var ss=document.getElementById(obj_name);
  var nodes=document.getElementsByTagName("UL");
  var s=document.getElementById('outer').getElementsByTagName('ul');
 
 for(i=1;i<=nodes.length;i++){
if(nodes[i].id.indexOf("item")<0)
continue;
else
s++;

 }
  
  
  if (ss.className=="none") 
  {
  
  for(i=1;i<=s.length;i++)
  {
  document.getElementById("item"+ i).className="none";
  }
  ss.className="nomorl";
  }
  else
  {
  ss.className="none";
  }
}

</script>
我按照六楼的方法加进去，没反应，我把它修改了下，测试后发现s++后面加一个alert(s)循环次数是对的，可加在循环体外面警告框也没了，不知道是什么原因

Answer 8

我是要你把我写的for 替换你原来写的for