ajax阻止表单跳转 本帖最后由 tingaining 于 2010-10-12 12:52:36 编辑 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 return false;以阻止提交 <script type="text/javascript">jQuery(function($){$("#user_name").blur(function(){var user_name = $("#user_name").val();var query = new Object();query.m = "Ajax";query.a = "user_name";query.user_name = user_name;query.type = this.getAttribute("type");if(user_name == ''){$("#user_names").html("用户名不能为空!");return false;}$.ajax({url: "index.php",data: query,dataType: "json",success:function(json){if(json.type == 0) {$("#user_names").html("此用户名已经存在");$("#user_names").show();return false;} else {$("#user_names").hide();}}});});});</script> <script type="text/javascript">function checkUser(){ //将相面的ajax操作放到这里,如果想不让表单提交请return false;(默认返回true)}jQuery(function($){$("#user_name").blur(function(){var user_name = $("#user_name").val();var query = new Object();query.m = "Ajax";query.a = "user_name";query.user_name = user_name;query.type = this.getAttribute("type");if(user_name == ''){$("#user_names").html("用户名不能为空!");return;}$.ajax({url: "index.php",data: query,dataType: "json",async: false,//设置同步,异步不能实现楼主的要求success:function(json){if(json.type == 0) {$("#user_names").html("此用户名已经存在");$("#user_names").show();} else {$("#user_names").hide();}}});});});</script>表单部分代码:<form class="cmxform" id="commentForm" action="" method="post" onsubmit="return checkUser()"> <label for="user_name"> <span style="red">*</span>用户名</label> <input type="text" tabindex="2" id="user_name" name="user_name" class="minlength" minlength="6"/> <input type="button" id="user-submit" value="确认注册" /></form> 4楼的朋友:function checkUser(){//将相面的ajax操作放到这里,如果想不让表单提交请return false;(默认返回true)}在我这边没用,因为我是ajax那样判断的我的控制ajax的php是: public function user_name(){ $result = array ("type" => 0, "msg" => "", "html" => "" ); $user_name = $_REQUEST['user_name']; $username = D("User")->where("user_name = '$user_name'")->find(); if($username['user_name'] == $user_name){ $result['type'] = 0; }else { $result['type'] = 1; } echo json_encode ( $result ); } 用$("#user_name").blur(function(){})用这个东西去触发啊ajax 问题解决了,现在记录下来,仅供遇到跟我一样的同鞋学习:js代码1:<script type="text/javascript">jQuery(function($){ $("#user_name").blur(function(){ var user_name = $("#user_name").val(); var query = new Object(); query.m = "Ajax"; query.a = "user_name"; query.user_name = user_name; query.type = this.getAttribute("type"); if(user_name == ''){ $("#user_names").html("用户名不能为空!"); is_good = '0'; return; } $.ajax({ url: "index.php", data: query, async:false, dataType: "json", success:function(json){ if(json.type == 0) { $("#user_names").html("此用户名已经存在"); $("#user_names").show(); is_good = '0'; return; } else { $("#user_names").hide(); is_good = '1'; } } }); });});</script>js代码2:<script type="text/javascript">jQuery(function($){ $("#user-submit").click(function(){ $("#user_name").blur(); if(is_good == '0') return false; else $("#commentForm").submit(); });});</script>只想说变态两个字! 一段实现apply的Javascript代码 求在当前网页右键另存为的脚本 我想用JS做一个卡拉OK歌词逐字着色的效果,请大家给方法和意见! JS中有没有类似c中宏的概念 请问这段javascript 代码是经过加密吗?该怎么分析它? 有没有这样的JS库或组件?实现表格滚动 JS能不能实现 客户端向服务器上传文件 请各位推荐一下适合javascript的编辑器 关于参数传递问题 知道就说 点击的问题 jquery ui datepicker显示的日期选择框被select档住了
以阻止提交
jQuery(function($){
$("#user_name").blur(function(){
var user_name = $("#user_name").val();
var query = new Object();
query.m = "Ajax";
query.a = "user_name";
query.user_name = user_name;
query.type = this.getAttribute("type");
if(user_name == ''){
$("#user_names").html("用户名不能为空!");
return false;
}
$.ajax({
url: "index.php",
data: query,
dataType: "json",
success:function(json){
if(json.type == 0) {
$("#user_names").html("此用户名已经存在");$("#user_names").show();
return false;
} else {
$("#user_names").hide();}
}
});});
});
</script>
function checkUser(){
//将相面的ajax操作放到这里,如果想不让表单提交请return false;(默认返回true)
}jQuery(function($){
$("#user_name").blur(function(){
var user_name = $("#user_name").val();
var query = new Object();
query.m = "Ajax";
query.a = "user_name";
query.user_name = user_name;
query.type = this.getAttribute("type");
if(user_name == ''){
$("#user_names").html("用户名不能为空!");
return;
}
$.ajax({
url: "index.php",
data: query,
dataType: "json",
async: false,//设置同步,异步不能实现楼主的要求success:function(json){
if(json.type == 0) {
$("#user_names").html("此用户名已经存在");$("#user_names").show();
} else {
$("#user_names").hide();
}
}
});});
});
</script>表单部分代码:
<form class="cmxform" id="commentForm" action="" method="post" onsubmit="return checkUser()">
<label for="user_name">
<span style="red">*</span>用户名</label>
<input type="text" tabindex="2" id="user_name" name="user_name" class="minlength" minlength="6"/>
<input type="button" id="user-submit" value="确认注册" />
</form>
//将相面的ajax操作放到这里,如果想不让表单提交请return false;(默认返回true)
}
在我这边没用,因为我是ajax那样判断的我的控制ajax的php是:
public function user_name(){
$result = array ("type" => 0, "msg" => "", "html" => "" );
$user_name = $_REQUEST['user_name'];
$username = D("User")->where("user_name = '$user_name'")->find();
if($username['user_name'] == $user_name){
$result['type'] = 0;
}else {
$result['type'] = 1;
}
echo json_encode ( $result );
}
})
用这个东西去触发啊ajax
js代码1:
<script type="text/javascript">
jQuery(function($){
$("#user_name").blur(function(){
var user_name = $("#user_name").val();
var query = new Object();
query.m = "Ajax";
query.a = "user_name";
query.user_name = user_name;
query.type = this.getAttribute("type");
if(user_name == ''){
$("#user_names").html("用户名不能为空!");
is_good = '0';
return;
}
$.ajax({
url: "index.php",
data: query,
async:false,
dataType: "json",
success:function(json){
if(json.type == 0) {
$("#user_names").html("此用户名已经存在");
$("#user_names").show();
is_good = '0';
return;
} else {
$("#user_names").hide();
is_good = '1';
}
}
});
});
});
</script>
js代码2:
<script type="text/javascript">
jQuery(function($){
$("#user-submit").click(function(){
$("#user_name").blur();
if(is_good == '0')
return false;
else
$("#commentForm").submit();
});
});
</script>只想说变态两个字!