请教几个正则表达式

Question

比如我要查一个手机号码中的最后四位是不是aabb或者abab或者aaab的形式，该如何写表达式？
如果谁厉害点帮我1234、3456等这样递增的该如何写？

Answer 1

aabb (\d)\1(\d)\2$
abab (\d\d)\1$
aaab (\d)\1\1\d$

Answer 2

//aabb，允许aaaa
(\d)\1(\d)\2$
//abab，允许aaaa
(\d)(\d)\1\2$
//aaab，允许aaaa
(\d)\1\1\d$
//同时允许
(?:(\d)\1(\d)\2|(\d)(\d)\3\4|(\d)\5\5\d)$//以上如果不允许aaaa，第二个(\d)改为((?!\1)\d)
//如aabb，不允许aaaa
(\d)\1((?!\1)\d)\2$//递增如果只是4位正则勉强可以做到，基本上类似于穷举了，意义不大，此为不允许7890
(0(?=1)|1(?=2)|2(?=3)|3(?=4|$)|4(?=5|$)|5(?=6|$)|6(?=7|$)|7(?=8|$)|8(?=9|$)|9(?=0|$)){4}$
//如果允许7890
(0(?=1|$)|1(?=2)|2(?=3)|3(?=4|$)|4(?=5|$)|5(?=6|$)|6(?=7|$)|7(?=8|$)|8(?=9|$)|9(?=0|$)){4}$

Answer 3

/^\d{7}(\d)\1(\d)\2$/ //aabb
/^\d{7}(\d)(\d)\1\2$/   //abab
/^\d{7}(\d)\1\1\d$/ //aaab
后2个不会写.