<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>itcast.cn用户名校验ajax实例</title>
<script type="text/javascript" src="jslib/verifyown.js"></script>
</head>
<body>
<form action="aa.jsp">
用户名:<input type="text" id="userName" onclick="verify()"/> <span id="result"></span><br />
密码:<input type="text" id="password" />
<input type="submit" value="提交"/>
</form></body>
</html>var xmlhttp;
function verify() {
var userName = document.getElementById("userName").value;
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
if (xmlhttp.overrideMimeType) {
xmlhttp.overrideMimeType("text/xml");
}
} else if (window.ActiveXObject) {
var activexName = ["MSXML2.XMLHTTP","Microsoft.XMLHTTP"];
for (var i = 0; i < activexName.length; i++) {
try{
xmlhttp = new ActiveXObject(activexName[i]);
break;
} catch(e){
}
}
}
if (!xmlhttp) {
alert("XMLHttpRequest对象创建失败!!");
return;
} else {
//alert(xmlhttp.readyState);
} xmlhttp.onreadystatechange = callback; xmlhttp.open("GET","AJAXServer?name="+ userName,true); xmlhttp.send(null);
}//回调函数
function callback() {
if (xmlhttp.readyState == 4) {
if (xmlhttp.status == 200) {
var responseText = xmlhttp.responseText;
var divNode = document.getElementById("result");
divNode.innerHTML = responseText;
} else {
alert("出错了!!!");
}
}
}现在鼠标得点到input框上才能提交,不点不提交。怎么让他光标离开就提交?
另外这样即便是用户名存在表单也提交了,怎么让用户名不存在的时候才能正确的提交,错误的时候提交不了。
谢谢了
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>itcast.cn用户名校验ajax实例</title>
<script type="text/javascript" src="jslib/verifyown.js"></script>
</head>
<body>
<form action="aa.jsp">
用户名:<input type="text" id="userName" onclick="verify()"/> <span id="result"></span><br />
密码:<input type="text" id="password" />
<input type="submit" value="提交"/>
</form></body>
</html>var xmlhttp;
function verify() {
var userName = document.getElementById("userName").value;
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
if (xmlhttp.overrideMimeType) {
xmlhttp.overrideMimeType("text/xml");
}
} else if (window.ActiveXObject) {
var activexName = ["MSXML2.XMLHTTP","Microsoft.XMLHTTP"];
for (var i = 0; i < activexName.length; i++) {
try{
xmlhttp = new ActiveXObject(activexName[i]);
break;
} catch(e){
}
}
}
if (!xmlhttp) {
alert("XMLHttpRequest对象创建失败!!");
return;
} else {
//alert(xmlhttp.readyState);
} xmlhttp.onreadystatechange = callback; xmlhttp.open("GET","AJAXServer?name="+ userName,true); xmlhttp.send(null);
}//回调函数
function callback() {
if (xmlhttp.readyState == 4) {
if (xmlhttp.status == 200) {
var responseText = xmlhttp.responseText;
var divNode = document.getElementById("result");
divNode.innerHTML = responseText;
} else {
alert("出错了!!!");
}
}
}现在鼠标得点到input框上才能提交,不点不提交。怎么让他光标离开就提交?
另外这样即便是用户名存在表单也提交了,怎么让用户名不存在的时候才能正确的提交,错误的时候提交不了。
谢谢了
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>itcast.cn用户名校验ajax实例</title>
<script type="text/javascript" src="jslib/verifyown.js"></script>
</head>
<body>
<form action="aa.jsp">
用户名:<input type="text" id="userName" onblur="verify()"/> <span id="result"></span><br />
密码:<input type="text" id="password" onblur="verify()"/>
<input type="submit" value="提交"/>
</form></body>
</html>
<script>
var xmlhttp;
function verify() {
var userName = document.getElementById("userName").value;
var password = document.getElementById("password").value;
if(!userName || !password)return false;//当两个都username或者password没有填的时候
// if(userName || password)return false;//同上相反的时候
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
if (xmlhttp.overrideMimeType) {
xmlhttp.overrideMimeType("text/xml");
}
} else if (window.ActiveXObject) {
var activexName = ["MSXML2.XMLHTTP","Microsoft.XMLHTTP"];
for (var i = 0; i < activexName.length; i++) {
try{
xmlhttp = new ActiveXObject(activexName[i]);
break;
} catch(e){
}
}
}
if (!xmlhttp) {
alert("XMLHttpRequest对象创建失败!!");
return;
} else {
//alert(xmlhttp.readyState);
} xmlhttp.onreadystatechange = callback; xmlhttp.open("GET","AJAXServer?name="+ userName,true); xmlhttp.send(null);
}//回调函数
function callback() {
if (xmlhttp.readyState == 4) {
if (xmlhttp.status == 200) {
var responseText = xmlhttp.responseText;
var divNode = document.getElementById("result");
divNode.innerHTML = responseText;
} else {
alert("出错了!!!");
}
}
}
</script>
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>itcast.cn用户名校验ajax实例</title>
<script type="text/javascript" src="jslib/verifyown.js"></script>
</head>
<body>
<form action="aa.jsp">
用户名:<input type="text" id="userName" onblur="verify()"/> <span id="result"></span><br />
密码:<input type="text" id="password" onblur="verify()"/>
<input type="submit" value="提交"/>
</form></body>
</html>
<script>
var xmlhttp;
function verify() {
var userName = document.getElementById("userName").value;
var password = document.getElementById("password").value;
if(userName)return false;
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
if (xmlhttp.overrideMimeType) {
xmlhttp.overrideMimeType("text/xml");
}
} else if (window.ActiveXObject) {
var activexName = ["MSXML2.XMLHTTP","Microsoft.XMLHTTP"];
for (var i = 0; i < activexName.length; i++) {
try{
xmlhttp = new ActiveXObject(activexName[i]);
break;
} catch(e){
}
}
}
if (!xmlhttp) {
alert("XMLHttpRequest对象创建失败!!");
return;
} else {
//alert(xmlhttp.readyState);
} xmlhttp.onreadystatechange = callback; xmlhttp.open("GET","AJAXServer?name="+ userName,true); xmlhttp.send(null);
}//回调函数
function callback() {
if (xmlhttp.readyState == 4) {
if (xmlhttp.status == 200) {
var responseText = xmlhttp.responseText;
var divNode = document.getElementById("result");
divNode.innerHTML = responseText;
} else {
alert("出错了!!!");
}
}
}
</script>
<input type="submit" value="提交" onclick="CheckForm()"/>
if(document.getElementById("divNode").outerhtml == "不存在的文本字符" && document.getElementById("userName").value == "")
{
alert("asda");
}
直接在verify()加不可以吗?
这个加在哪啊?还是单独写个函数啊?
{
alert("asd");
return;
}function verify() {
if(userName.value == "")
{
alert("123");
return;
}}
现在即便是空、而却用户名也存在他也可以正常的提交表单,我想不让他提交。