extjs editorgridpanel 更改后的数据提交到后台

Question

前台代码
var m = MyEditorGridUi.getStore().getModifiedRecords(); //获取修改记录
                    if (m.length == 0) {
                        alert("没有数据");
                        return false;
                    }
                    var sSend = "["
                    for (var i = 0, len = m.length; i < len; i++) {
                        sSend = sSend + "{SerialKey:" + m[i].data['SerialKey'] + ", ModuleName:'" + m[i].data['ModuleName'] +"', PreCode:'" + m[i].data['PreCode'] + ", DateFormat:'" + m[i].data['DateFormat'] + ", IndexCode:'" + m[i].data['IndexCode']+", Sepa:'" + m[i].data['Sepa'] + "'}";
                        if (i < len - 1)
                            sSend = sSend + ","
                    }
                    sSend = sSend + "]";                    sSend = Ext.util.JSON.encode(sSend);
                    alert(sSend);
                    Ext.Ajax.request({
                    url: 'UI/SysSet/CodeFormatSet.aspx?opera_name=Update',
                    method: 'POST',
                    success: function(result, request) {
                        alert('成功' + result.responseText);
                    },
                    failure: function(result, request) {
                        alert('失败' + result.responseText);
                    },
                    params: { data: sSend } 后台怎么写呢
我用的是.net(C#),获取到的参数是个字符串，能使用json吗，怎么用呢，不太希望去操作String类，有没有更好的方法

Answer 1

如何进行反序列化呢？？
string strParams=Request.Params["data"].ToString();
            
                JavaScriptSerializer serializer = new JavaScriptSerializer();
                oSerialCon = serializer.Deserialize<SerialConstruct>(strParams);
这是我后台写的方法,SerialConstruct是我定义的类，里面有SerialKey，ModuleName等属性;

Answer 2

public class SerialConstruct
{
   private string _ModuleName;
   public ModuleName
   {
       get {return _ModuleName;}
       set {_ModuleName=value;}
   }
}
string strParams=Request.Params["data"].ToString();
            
                JavaScriptSerializer serializer = new JavaScriptSerializer();
                oSerialCon = serializer.Deserialize<SerialConstruct>(strParams);
oSerialCon 反回null
怎么回事

Answer 3

平平在吗，再问个小问题 Ext.Ajax.request({
                    url: 'UI/SysSet/CodeFormatSet.aspx?opera_name=Update',
                    method: 'POST',
                    success: function(result, request) {
                        alert('成功' + result.responseText);
                    },
                    failure: function(result, request) {
                        alert('失败' + result.responseText);
                    },后台(C#)操作成功后，返回什么样子的值呀？？？

Answer 4

返回什么值你自己定
可以是这样
"{ 'success':true,'message':'操作成功！'}"