如何用JS或jquery复制json对象然后组合成新的json

Question

有个json数据var json = [{"title":"广东","zip":"520","area":[{"a":"10","b":"20"}]},
           {"title":"广西","zip":"320","area":[{"a":"10","b":"20"}]},
           {"title":"山东","zip":"820","area":[{"a":"10","b":"20"}]},
           {"title":"黑龙江","zip":"720","area":[{"a":"10","b":"20"}]}];现在通过查找zip大于300小于800的出来。然后组合成一个新json对象$(json).each(function(index,obj){
  
if(parseInt(this.zip) > 300 && parseInt(this.zip) < 800)
{
   alert(obj);
   //此处弹出了符合条件的json对象。但我不懂得如何将该对象组合成新对象，以便再次操作得到的新json
}})

Answer 1

$(json).each(function(index,obj){
  
if(parseInt(this.zip) > 300 && parseInt(this.zip) < 800)
{
  alert(obj);
  //此处弹出了符合条件的json对象。但我不懂得如何将该对象组合成新对象，以便再次操作得到的新json
}
alert(obj[index]);
$.each(obj[index], function (key, data) {
    alert(key + "-" + data[key]);
});
})

Answer 2

var json = [{"title":"广东","zip":"520","area":[{"a":"10","b":"20"}]},
  {"title":"广西","zip":"320","area":[{"a":"10","b":"20"}]},
  {"title":"山东","zip":"820","area":[{"a":"10","b":"20"}]},
  {"title":"黑龙江","zip":"720","area":[{"a":"10","b":"20"}]}];
  var l=json.length-1;
  var newJson=[];
  for (var i=0;i<=l;i++)
  {
var t=json[i];
if(parseInt(t.zip) > 300 && parseInt(t.zip) < 800)
{
newJson.push(t);
}
  }
  //test
  var r=newJson.length-1;
  for(var i=0;i<=r;i++)
  {
var t=newJson[i];
alert(t.title+' '+t.zip+' '+t.area[0].a+' '+t.area[0].b);
  }

Answer 3

var json = [{"title":"广东","zip":"520","area":[{"a":"10","b":"20"}]},
  {"title":"广西","zip":"320","area":[{"a":"10","b":"20"}]},
  {"title":"山东","zip":"820","area":[{"a":"10","b":"20"}]},
  {"title":"黑龙江","zip":"720","area":[{"a":"10","b":"20"}]}];
  var newJson=[];
  for(var i=0;i<json.length;i++){
      if(parseInt(json[i].zip)>300&&parseInt(json[i].zip<800)){
          newJson.push(json[i]);
     }
  }
alert(json);
alert(json.length);