function CheckInputMsg(Str1,ActionId,DivLoad){
var ajax = InitAjax();//Ajax object
ajax.open("GET",url,true);//use Get do requesting....
ajax.onreadystatechange=function(){//request state
if(ajax.readyState == 4){
if(ajax.status == 200){
blnResult=ajax.responseText;
}
}}如何将blnResult返回到最外CheckInputMsg函数中????
var ajax = InitAjax();//Ajax object
ajax.open("GET",url,true);//use Get do requesting....
ajax.onreadystatechange=function(){//request state
if(ajax.readyState == 4){
if(ajax.status == 200){
blnResult=ajax.responseText;
}
}}如何将blnResult返回到最外CheckInputMsg函数中????
解决方案 »
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