<script type="text/javascript">var productDiv=new Array();
productDiv=[["showgoods1,imggoods1","productlist1"],["showgoods2,imggoods2","productlist2"];var playnum=1;function showproductdiv(id){
if(id==0){id=playnum;}
for(i=1;i<=4;i++){
if(i==id){
$("#showgoods"+id).style.display="inline";
$("#imggoods"+id).style.display="none";
$("#productlist"+id).style.display="";
}else{
$("#showgoods"+i).style.display="none";
$("#imggoods"+i).style.display="";
$("#productlist"+i).style.display="none";
}
}
if(playnum==4){playnum=1}else{playnum++}
}
var myplay;
function ProductDivPlay(id){
if(id==""){id=0}else{playnum=id} myplay=setInterval("showproductdiv(0)",8000);
}function ProductDivStop(){ clearInterval(myplay);
}
ProductDivPlay(0);</script><span id="imggoods1" class="nowbg" style="display: none" onmouseover="showproductdiv(1);">第一张图</span>
<span id="showgoods1" class="changebg" onmouseout="ProductDivPlay(1);" onmouseover="ProductDivStop();">第一张图</span>
<span id="imggoods2" class="nowbg" onmouseover="showproductdiv(2);">第二张图<span>
<span id="showgoods2" class="changebg" onmouseout="ProductDivPlay(2);" onmouseover="ProductDivStop();" style="display: none;">第二张图</span>错误提示:
$("#showgoods" + id).style is undefined
[Break on this error] $("#showgoods"+id).style.display="inline";
解决方案 »
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