除尽

Question

如果判断两个数通否除尽?数可以为整数或小数。

Answer 1

    var x1=1.5,x2=0.2;
    alert((1.5/0.2)%1==0)
    alert((1.5/0.3)%1==0)

Answer 2

    alert(check(1.5,0.2))
    alert(check(1.5,0.3))
    alert(check(15,2))
    alert(check(15,3))
function check(x1,x2){
    if(x2==0)return false;
    return (x1/x2)%1==0
}

Answer 3

function check(x1,x2){
    if(x2==0)return false;
    return x1/x2*x2==x1
}

Answer 4

function check(x1,x2){
    return (x1 * Math.pow(10,100) / x2).toString().indexOf('.') == -1;
}
alert(check(2,3));
alert(check(2,5));

Answer 5

alert(check(10,3));
alert(check(7,9));
alert(check(4,5)); 
全都是true
不对

Answer 6

alert(check(1.5,0.3));
alert(check(1.5,0.2));
为false;不对，应该是true;

Answer 7

http://topic.csdn.net/u/20090402/20/7afc7279-5701-4d0b-a39f-03588d6583ed.html

Answer 8

......<script type="text/javascript">
    alert(check(10,3)); 
    alert(check(7,9)); 
    alert(check(4,5)); 
    alert(check(1.5,0.2))
    alert(check(1.5,0.3))
    alert(check(15,2))
    alert(check(15,3))
    alert(check(1.5,2))
function check(x1,x2){
    if(x2==0)return false;
    while(x1%1!=0)x1=x1*10;
    while(x2%1!=0)x2=x2*10;
    
    var r1=getItem(x1);
    var r2=getItem(x2);
    for(var i=r2.length-1;i>=0;i--){
        for(var j=0,k=0;j<r1.length;j++){
            if(k==0 && r2[i]==r1[j]){
                k=1;
                r2.pop();
                delete r1[j];
            }
        }
    }
    
    return r2.length==0;
}
function getItem(x){
    var r=[];
    for(var i=2;i<=x;i++){
        if(x%i==0){;
            if(i!=2 && i!=5)r[r.length]=i;
            x=x/i;
            i-=1;
        }
    }
    return r;
}
</script>

Answer 9

......<script type="text/javascript">
    alert(check(10,3)); 
    alert(check(7,9)); 
    alert(check(4,5)); 
    alert(check(1.5,0.2))
    alert(check(1.5,0.3))
    alert(check(15,2))
    alert(check(15,3))
    alert(check(1.5,2))
function check(x1,x2){
    if(x2==0)return false;
    while(x1%1!=0)x1=x1*10;
    while(x2%1!=0)x2=x2*10;
    
    var r1=getItem(x1);
    var r2=getItem(x2);
    for(var i=r2.length-1;i>=0;i--){
        for(var j=0,k=0;j<r1.length;j++){
            if(k==0 && r2[i]==r1[j]){
                k=1;
                r2.pop();
                delete r1[j];
            }
        }
    }
    
    return r2.length==0;
}
function getItem(x){
    var r=[];
    for(var i=2;i<=x;i++){
        if(x%i==0){;
            if(i!=2 && i!=5)r[r.length]=i;
            x=x/i;
            i-=1;
        }
    }
    return r;
}
</script>

Answer 10

<script>
 var isDivisible = function(num1,num2){
  new String(num1/num2*1000000000000000).indexOf(".") == -1?alert("除尽"):alert("除不尽")
 }
 isDivisible(7,9);
 isDivisible(10,3); 
 isDivisible(10,5); 
 isDivisible(1.5,0.2);
 isDivisible(1.5,0.3);
 isDivisible(15,2);
 isDivisible(15,3);
 isDivisible(1.5,2);
</script>

Answer 11

isDivisible(1.5,0.0000000000000000000002);

Answer 12

javascript要做到短小精悍，正常情况下满足需求就可以了。
如此贴，正常情况下一般不会出现0.0000000000000000000002这样的数据。