例如:
[2010-01-28]如下代码用正则怎么过滤[3分]本字符串特性:
1、[2010-01-28]这一部分在字符串最前面
2、这一部分是以[]括起来
2、[]里的内容不固定如何取出[2010-01-28]这一部分,希望用正则。另外用JS的话,如何用最简单的方式输出当前日期,格式如:[2010-01-28]
[2010-01-28]如下代码用正则怎么过滤[3分]本字符串特性:
1、[2010-01-28]这一部分在字符串最前面
2、这一部分是以[]括起来
2、[]里的内容不固定如何取出[2010-01-28]这一部分,希望用正则。另外用JS的话,如何用最简单的方式输出当前日期,格式如:[2010-01-28]
<script>
var str = "[2010-01-28]如下代码用正则怎么过滤[3分] ";
var hits = str.match(/^\[.*?\]/ig);
alert(hits);
</script>但如何用最少的JS代码获得如下日期格式?
[2010-01-28]
Date.prototype.format = function(mask) {
var d = this;
var zeroize = function (value, length) {
if (!length) length = 2;
value = String(value);
for (var i = 0, zeros = ''; i < (length - value.length); i++) {
zeros += '0';
}
return zeros + value;
};
return mask.replace(/"[^"]*"|'[^']*'|\b(?:d{1,4}|m{1,4}|M{1,4}|yy(?:yy)?|([hHMstT])\1?|[lLZ])\b/g, function($0) {
switch($0) {
case 'd': return d.getDate();
case 'dd': return zeroize(d.getDate());
case 'ddd': return ['Sun','Mon','Tue','Wed','Thr','Fri','Sat'][d.getDay()];
case 'dddd': return ['Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday'][d.getDay()];
case 'M': return d.getMonth() + 1;
case 'MM': return zeroize(d.getMonth() + 1);
case 'MMM': return ['Jan','Feb','Mar','Apr','May','Jun','Jul','Aug','Sep','Oct','Nov','Dec'][d.getMonth()];
case 'MMMM':
return ['January','February','March','April','May','June','July','August','September','October','November','December'][d.getMonth()];
case 'yy': return String(d.getFullYear()).substr(2);
case 'yyyy': return d.getFullYear();
case 'h': return d.getHours() % 12 || 12;
case 'hh': return zeroize(d.getHours() % 12 || 12);
case 'H': return d.getHours();
case 'HH': return zeroize(d.getHours());
case 'm': return d.getMinutes();
case 'mm': return zeroize(d.getMinutes());
case 's': return d.getSeconds();
case 'ss': return zeroize(d.getSeconds());
case 'l': return zeroize(d.getMilliseconds(), 3);
case 'L': var m = d.getMilliseconds();
if (m > 99) m = Math.round(m / 10);
return zeroize(m);
case 'tt':
return d.getHours() < 12 ? 'am' : 'pm';
case 'TT': return d.getHours() < 12 ? 'AM' : 'PM';
case 'Z': return d.toUTCString().match(/[A-Z]+$/);
// Return quoted strings with the surrounding quotes removed
default: return $0.substr(1, $0.length - 2);
}
});
};
var date = new Date();
alert('['+date.format("yyyy-MM-dd")+']'); </script>