这个菜单的链接该如何加？？

解决方案 »

免费领取超大流量手机卡，每月29元包185G流量+100分钟通话, 中国电信官方发货

lz
--------------- str       +=       " <tr> <td       onclick='parent.oPopup.hide();'> <a href=''>第四项</a> </td>
这样???<script language="JavaScript" type="text/JavaScript">
    var oPopup = window.createPopup();
    function popUp()
    {
if(!oPopup.isOpen)//判断是否显示
{
  var str = " <body> <table id=mypopup border=0 cellpadding=0 cellspacing=0 width=200 height=100 style='background: menu'> ";
  str += " <tr> <td onclick='parent.oPopup.hide();' style='font-size:   12pt'   > 11111 </td> </tr> ";
  str += " <tr> <td onclick='parent.oPopup.hide();'> 2222 </td> </tr> ";
  str += " <tr> <td onclick='parent.oPopup.hide();'> 第三项 </td> </tr> ";
  str += " <tr> <td onclick='parent.oPopup.hide();'> 第四项 </td> </tr> ";
  str += " </table> </body> ";
  var oPopBody = oPopup.document.body;
  oPopBody.style.backgroundColor = "buttonface";
  oPopBody.style.border = "solid black 0px";
  oPopBody.innerHTML = str;

  var p=GetDivPos();
  var x = p.x;
  var y = p.y+window.screenTop;
  var w = 182;
  var h = 97;
  oPopup.show(x, y, w, h);
}
}
//获取div的绝对位置
function GetDivPos()
{
var a=document.getElementById("a");
var p=new Object();
p.x=a.offsetLeft;
p.y=a.offsetHeight+a.offsetTop;
o=a.offsetParent;
while(o)
{
  p.x+=o.offsetLeft;
  p.y+=o.offsetTop;
  o=o.offsetParent;
}
return p;
}
    </script>
<div id="a"   onMouseOver="popUp();"> dddddd </div>
这样,用js改变parent的locationstr += " <tr> <td onclick='parent.oPopup.hide();'>"
+"<a href='http://www.csdn.net' onclick='parent.location.href=this.href;'>"
+"第四项</a></td> </tr> ";