split正则分割字符串（难）

Question

字符串：color-white-black--name-'a-b'-ppg--style-'c''-d'-beauty-fashion
1. --表示组的分隔符。
2. -表示分隔符。
3. 字符串内有-或者’的字符串两边加'',如a-b由于含有-，表示为'a-b',c'-d表示为'c''-d'。
3. 分割的字符串放入二维数组。
所以上述字符串分割后的结果是：
一个二维数组，数组每项如下：
arr[0][0] = "color";
arr[0][1] = "white";
arr[0][2] = "black";
arr[1][0] = "name";
arr[1][1] = "a-b";
arr[1][2] = "ppg";
arr[2][0] = "style";
arr[2][1] = "c'-d";
arr[2][2] = "beauty";
arr[2][3] = "fashion";

Answer 1

var s = "color-white-black--name-'a-b'-ppg--style-'c''-d'-beauty-fashion";
var a=[];
var b = s.split("--");
for(var i=0;i<b.length;i++){
   a[i] = parse(b[i]);
}
for(var i=0;i<b.length;i++){
   for(var j=0;j<a[i].length;j++)
        alert("a["+i+"]["+j+"] = " + a[i][j]);
}
function parse(str){
    arr = [];
    var bqf=false;
    var s = "";
    for(var i=0;i<str.length;i++){
        var c  = str.charAt(i);
        switch(c){
           case '-':if(!bqf){
                        if(s!="") arr.push(s);
                        s = "";
                    }
                    else s +=c;
                    break;  
           case "'":if(bqf){
                        var tc = str.charAt(i+1);
                        if(tc=="'"){
                             s += "'";
                             i++;
                        }
                        else bqf = false;
                    }
                    else{
                        bqf = true;   
                    }
                    break; 
           default: s +=c;
        }
    }
    if(s!="") arr.push(s);
    return arr;
}

Answer 2

var s = "color-white-black--name-'a-b'-ppg--style-'c''-d'-beauty-fashion";
var a=[];
var b = s.split("--");
for(var i=0;i<b.length;i++){
   a[i] = parse(b[i]);
}
for(var i=0;i<b.length;i++){
   for(var j=0;j<a[i].length;j++)
        alert("a["+i+"]["+j+"] = " + a[i][j]);
}
function parse(str){
    arr = [];
    var bqf=false;
    var s = "";
    for(var i=0;i<str.length;i++){
        var c  = str.charAt(i);
        switch(c){
           case '-':if(!bqf){
                        if(s!="") arr.push(s);
                        s = "";
                    }
                    else s +=c;
                    break;  
           case "'":if(bqf){
                        var tc = str.charAt(i+1);
                        if(tc=="'"){
                             s += "'";
                             i++;
                        }
                        else bqf = false;
                    }
                    else{
                        bqf = true;   
                    }
                    break; 
           default: s +=c;
        }
    }
    if(s!="") arr.push(s);
    return arr;
}

Answer 3

<script type="text/javascript">
<!--
var str = "color-white-black--name-'a-b'-ppg--style-'c''-d'-beauty-fashion";
arr = str.replace(/'([a-z]+)-([a-z]+)'/i,"$1*$2").replace(/'(.*?)''-(.*?)'/,"$1'*$2").split("--");
for(var i = 0; i < arr.length; i++){
for(var j = 0; j < arr[i].split('-').length; j++){
document.write(arr[i].split("-")[j].replace("*","-")+"<br/>");
}
}
//-->
</script>

Answer 4

<script type="text/javascript">
<!--
var str = "color-white-black--name-'a-b'-ppg--style-'c''-d'-beauty-fashion";
arr = str.replace(/'([a-z]+)-([a-z]+)'/i,"$1*$2").replace(/'(.*?)''-(.*?)'/,"$1'*$2").split("--");// 测试CSDN显示代码滚动条BUG
for(var i = 0; i < arr.length; i++){
for(var j = 0; j < arr[i].split('-').length; j++){
document.write(arr[i].split("-")[j].replace("*","-")+"<br/>");
}
}
//-->
</script>CSDNzh