jquery 请问怎样获取list+n的n值然后append含n的节点？

Question

本帖最后由 mingfish 于 2009-08-28 16:26:31 编辑

Answer 1

<script src="js/jquery-1.3.2.js" type="text/javascript"> </script>
<script>
window.onload = function(){
$("li").each(function(){
var s = $(this)[0].className
var n = s.substr(4, s.length-4);
$(this).append("<span>type=" + n + "</span>");
})
}
</script>
<ul>
    <li class="list1">
        <a>aa</a>
    </li>
    <li class="list2">
        <a>aa</a>
    </li>
    <li class="list3">
        <a>aa</a>
    </li>
</ul>

Answer 2

如果是按顺序的这样就好了<script>
$(document).ready(function()
   {
$("ul").find("li").each(function(i) {
 alert($(this).html())
$(this).append('<span>'+i+'</span>')
});
   });
</script>
<ul>
    <li class="list1">
        <a>aa</a>
    </li>
    <li class="list2">
        <a>bb</a>
    </li>
    <li class="list3">
        <a>cc</a>
    </li>
</ul>