关于多张表的json该如何解析~？

Question

一个dataset中包含多张表，将这个dataset解析为json并输出到屏幕上为：
      {   "Head ": 
          [ 
            {   
                "name ": "aaa ", 
                "sex ": "男 ", 
                "age ": "15 ", 
                "date ": "2009-6-29   23:00:44 " 
              },   
        
            {   
                "name ": "bbb ", 
                "sex ": "男 ", 
                "age ": "21 ", 
                "date ": "2009-6-29   18:24:53 " 
              },   
        
            {   
                "name ": "ccc ", 
                "sex ": "男 ", 
                "age ": "40 ", 
                "date ": "2009-6-29   18:18:12 " 
              }   
          ] 
      } 
     { "Head":[ { "time":"0"} ]}
     { "Head":[ { "Pcount":"1"} ]}
     { "Head":[ { "Ccount":"2"} ]} 
请问这样的json该怎么解析呀？？？

Answer 1

eval函数不就可以解析了吗 ？ 

Answer 2

  protected void Page_Load(object sender, EventArgs e)
    {
        if (!IsPostBack)
        {
            Response.Clear();
            Response.Charset = "utf-8";
            Response.Buffer = true;
            this.EnableViewState = false;
            Response.ContentEncoding = System.Text.Encoding.UTF8;
            Response.ContentType = "text/plain";
            Response.Write(GetLikeUserName());
            Response.Flush();
            Response.Close();
            Response.End();
        }
    }
    private string GetLikeUserName()
    {
        string[] str ={ "January", "Ceshi", "jQuery", "josn", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };
        StringBuilder sbstr = new StringBuilder();
        sbstr.Append("[");
        for (int i = 0; i < str.Length; i++)
        {
            if (i == str.Length - 1)
            {
                sbstr.Append("{name:'" + str[i] + "',to:'最后中文测试" + i + "'}");
            }
            else
            {
                sbstr.Append("{name:'" + str[i] + "',to:'中文测试" + i + Request.QueryString["q"] + "'},");
            }
        }
        sbstr.Append("]");
        
        return sbstr.ToString();
    }
输出的格式为：
[{name:'January',to:'中文测试0z'},{name:'Ceshi',to:'中文测试1z'}, {name:'jQuery',to:'中文测试2z'},{name:'josn',to:'中文测试3z'}, {name:'February',to:'中文测试4z'},{name:'March',to:'中文测试5z'}, {name:'April',to:'中文测试6z'},{name:'May',to:'中文测试7z'},{name:'June',to:'中文测试8z'},{name:'July',to:'中文测试9z'},{name:'August',to:'中文测试10z'}, {name:'September',to:'中文测试11z'},{name:'October',to:'中文测试12z'}, {name:'November',to:'中文测试13z'},{name:'December',to:'最后中文测试14'}]
获取到该数据以后：通过eval(data）就可以转化了 

Answer 3

可以参考这里：http://topic.csdn.net/u/20090703/14/8d349262-8ca1-4bf5-998d-3a0712412149.html

Answer 4

using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.Text;public partial class josn_Default : System.Web.UI.Page
{
    DataTable DT = new DataTable();
    DataRow DR;
    DataColumn DC = new DataColumn();
    protected void Page_Load(object sender, EventArgs e)
    {
        if (!Page.IsPostBack)
        {
            ReturnDataTable();
            for (int i = 0; i < 10; i++)
                {
                    DR = DT.NewRow();
                    DR["ID"] = i;
                    DR["Title"] = "胡果" + i;
                    DT.Rows.Add(DR);
                }
                StringBuilder Builder = new StringBuilder();
                for (int j = 0; j < DT.Rows.Count; j++)
                {                    Builder.AppendFormat("ID:{0},Title:{1}", DT.Rows[j][0].ToString(), DT.Rows[j][1].ToString());
                }
                Response.Write(Builder.ToString());
        }
    }
    public void ReturnDataTable()
    {
        DC = new DataColumn();
        DC.ColumnName = "ID";
        DC.DataType = System.Type.GetType("System.Int32");
        DT.Columns.Add(DC);
        DC = new DataColumn();
        DC.ColumnName = "Title";
        DC.DataType = System.Type.GetType("System.String");
        DT.Columns.Add(DC);
    }
}

Answer 5

格式得调整
变量里的空格去掉
把最外层的同层级{}放到一个数组里[]<div id="json">
[
{"Head":

[ 
            {  
                "name": "aaa ", 
                "sex": "男 ", 
                "age": "15 ", 
                "date": "2009-6-29  23:00:44 " 
              },  
        
            {  
                "name": "bbb ", 
                "sex": "男 ", 
                "age": "21 ", 
                "date": "2009-6-29  18:24:53 " 
              },  
        
            {  
                "name": "ccc ", 
                "sex": "男 ", 
                "age": "40 ", 
                "date": "2009-6-29  18:18:12 " 
              }  
          ] 
      }, 
    { "Head":[ { "time":"0"} ]},
    { "Head":[ { "Pcount":"1"} ]},
    { "Head":[ { "Ccount":"2"} ]} 
]
</div>
<script>
var json = document.getElementById('json').innerHTML;
json = eval('('+json+')'); alert(json[0].Head[0].name); // aaa
alert(json[0].Head[0].sex); // 男
</script>

Answer 6

var json = {  "Head ":
          [
            { 
                "name ": "aaa ",
                "sex ": "男 ",
                "age ": "15 ",
                "date ": "2009-6-29  23:00:44 "
              }, 
       
            { 
                "name ": "bbb ",
                "sex ": "男 ",
                "age ": "21 ",
                "date ": "2009-6-29  18:24:53 "
              }, 
       
            { 
                "name ": "ccc ",
                "sex ": "男 ",
                "age ": "40 ",
                "date ": "2009-6-29  18:18:12 "
              } 
          ]
      };
function map(elems,callback){
var arr = [];
for ( var i = 0; i < elems.length; i++ ) {
var value = callback(elems[i],i);
if(value!=null){
arr[arr.length] = value;
}
}
return arr.concat.apply([],arr);
}  var t = map(_xkx.Head,function(row){
  return {
  name : row.name
                                //helping yourself
  }
  });
 
  alert(t[0].name);
  alert(t[1].name); 

Answer 7

<div id="json">
[
        {"Head":
        
        [ 
            {  
                "name": "aaa ", 
                "sex": "男 ", 
                "age": "15 ", 
                "date": "2009-6-29  23:00:44 " 
              },  
        
            {  
                "name": "bbb ", 
                "sex": "男 ", 
                "age": "21 ", 
                "date": "2009-6-29  18:24:53 " 
              },  
        
            {  
                "name": "ccc ", 
                "sex": "男 ", 
                "age": "40 ", 
                "date": "2009-6-29  18:18:12 " 
              }  
          ] 
      }, 
    { "Head":[ { "time":"0"} ]},
    { "Head":[ { "Pcount":"1"} ]},
    { "Head":[ { "Ccount":"2"} ]} 
]
</div>
<script>
    var json = document.getElementById('json').innerHTML;
    json = eval('('+json+')');    alert(json[0].Head[0].name); // aaa
    alert(json[0].Head[0].sex); // 男
</script>