怎么用正则表达式取得地址的域名

Question

比如：http://www.zh28.com/news/20060213.html
这个字符串只截取http://www.zh28.com,其它的部分不要  .com、.cn等等都是这样

Answer 1

<script language=javascript>
var str="http://www.zh28.com/news/20060213.html"
re=/(http:\/\/[^\/]+)/
re.test(str)
alert(RegExp.$1)
</script>

Answer 2

<script language=javascript>
var str="http://www.zh28.com/news/20060213.html"
re=/^(http\://[a-z0-9\-\.]+\.[a-z]{2,3})(/\S*)?$/gi;
re.test(str)
alert(RegExp.$1)
</script>

Answer 3

<script language=javascript>
var str="http://www.zh28.com/news/20060213.html";
re=/(^http:\/\/[a-z0-9\-\.]+\.[a-z]{2,3})(\/\S*)?$/gi;
re.test(str);
alert(RegExp.$1);
</script>

Answer 4

这个更简单
<script language=javascript>
var str="http://www.zh28.com/news/20060213.html";
re=/(^http:\/\/[^\/]*)?/gi;
re.test(str);
alert(RegExp.$1);
</script>

Answer 5

把天外水火的改造了一下，呵呵，追加了.com,.cn制限<script language=javascript>
var str="http://www.zh28.cn/news/20060213.html"
re=/(http:\/\/[^\/]+(.com|.cn))/
re.test(str)
alert(RegExp.$1)
</script>

Answer 6

<script language=javascript>
var str="http://community.csdn.net/Expert/topic/5430/5430887.xml?temp=.443722";
re=/(^http:\/\/[a-z0-9\-\.]+\.[a-z]{2,3})(\/\S*)?(\?[a-z0-9]=[a-z0-9%])?(&[a-z0-9]=[a-z0-9%])*$/gi;
re.test(str);
alert(RegExp.$1);
</script>