如何通过js分离TempStr的值

Question

TempStr="var IPData = new Array(\"222.190.96.246\",\"\",\"江苏省\",\"南京市\"); ";
eval(TempStr);
user_ip=IPData[0];
user_sheng=IPData[2];
user_shi=IPData[3];

Answer 1

eval(TempStr);
user_ip = IPData[0];
user_sheng = IPData[2];
user_shi = IPData[3];

Answer 2

<script language="javascript">
var result="var IPData = new Array(\"222.190.96.246\",\"\",\"江苏省\",\"南京市\");"
var pattern=/".*?"/gi;
var array=result.match(pattern);
var tem="user_ip="+array[0]+" user_sheng="+array[2]+" user_shi="+array[3];
alert(tem);
</script>

Answer 3

各位啊，问题被你误解了！
先点下面链接
http://fw.qq.com/ipaddress
我通过AJAX 获得
TempStr=GetResStr(vUrl,"gb2312") 后，把
var IPData = new Array("222.190.96.246","","江苏省","南京市"); 
就赋给了TempStr 现要做分离222.190.96.246  江苏省 南京市

Answer 4

vUrl值就是http://fw.qq.com/ipaddress 

Answer 5

楼主先去看看 eval 函数的用途...

Answer 6

eval(TempStr);
user_ip = IPData[0];
user_sheng = IPData[2];
user_shi = IPData[3];

Answer 7

看明白了，问题不在JS
而是这段程序是asp

Answer 8

<script language="javascript">
<!--
var strLen
function getStr(s,n){var _n=2 ;if (n>=strLen-1)_n=3;return s.substr(1,s.length-_n)}
function setStr(s){return s.split("(")[1].split(",")}//"222.190.96.246","","江苏省","南京市")var str=setStr('var IPData = new Array("222.190.96.246","","江苏省","南京市")')
strLen=str.lengthuser_ip=getStr(str[0],0) 
user_sheng=getStr(str[2],2)
user_shi=getStr(str[3],3)alert(user_ip+"\n"+user_sheng+"\n"+user_shi)
//-->
</script>

Answer 9

<script language="javascript">
<!--
function setStr(s){return s.split('"')}var str=setStr('var IPData = new Array("222.190.96.246","","江苏省","南京市")')
user_ip=str[1] 
user_sheng=str[5]
user_shi=str[7]alert(user_ip+"\n"+user_sheng+"\n"+user_shi)
//-->
</script>

Answer 10

<script>
var str = 'var IPData = new Array("222.190.96.246","","江苏省","南京市");';
function setStr(str){
document.write ("<script>"+str+"</scr"+"ipt>")
alert(IPData[0] + '\n' + IPData[2] + '\n' + IPData[3]);
}
setStr(str)
</script>