下面这个方法好用,但只能获取1个RSS,现想获取多个如何实现啊
<script language="JavaScript1.2">
//Container for ticker. Modify its STYLE attribute to customize style:
var tickercontainer='';
var xmlsource="http://www.abc.com/rss/rss_110000.html";
var root;
var title;
var link; 
var items;
var item;
var images;
var image;
var description;
if (window.ActiveXObject)
{
   //document.write("Microsoft.XMLDOM");
   var xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
}
else if (document.implementation && document.implementation.createDocument)
{
   //document.write("document.implementation.createDocument");
   var xmlDoc= document.implementation.createDocument("","doc",null);
}
if (typeof xmlDoc!="undefined")
{
   //document.write(tickercontainer)
   xmlDoc.load(xmlsource);
}
function fetchxml()
{
   if (xmlDoc.readyState==4)
{output();}
   else
{setTimeout("fetchxml()",100);}
}
function output()
{  
   var temp="";
   root = xmlDoc.getElementsByTagName("channel")[0];
   title =root.getElementsByTagName("title")[0];
   //temp = title.firstChild.nodeValue +"<br>";
   items=root.getElementsByTagName("item");
   for(var i=0;i<=items.length-1&&i<15;i++)
   {
item=items[i];
title=item.getElementsByTagName("title")[0]; 
link=item.getElementsByTagName("link")[0];
description=item.getElementsByTagName("description")[0];
var imgAddress=description.firstChild.nodeValue;
imgAddress=imgAddress.substring(imgAddress.indexOf("src=\"")+5).substring(0,imgAddress.substring(imgAddress.indexOf("src=\"")+5).indexOf("\""));
temp = temp + "<font size=-1><a href=" + link.firstChild.nodeValue+ " target='_bank'>" + title.firstChild.nodeValue +"</a></font><br><br>";
//temp = temp +"<font size=-1>" + description.firstChild.nodeValue + "</font><br><br>";
document.getElementById("container").innerHTML = temp;
   }
}
if (window.ActiveXObject)
{
   fetchxml()
}
else if (typeof xmlDoc!="undefined")
{
   xmlDoc.onload=output
}</script>