现在要截取url的字符串问题如下
如果url是这样的形式showInfo.aspx?id=200701的话,即带参数的,则截取id的值200701,并将此值赋给一个input,如果只是showInfo.aspx的话,取不进行截取,
要求在页面装载执行此js以前没有写过js,求助一下,谢谢啊
如果url是这样的形式showInfo.aspx?id=200701的话,即带参数的,则截取id的值200701,并将此值赋给一个input,如果只是showInfo.aspx的话,取不进行截取,
要求在页面装载执行此js以前没有写过js,求助一下,谢谢啊
{
var IndexBegin = sQueryString.indexOf("id=") + "id=".length;
if(IndexBegin == -1)
return "";
var IndexEnd = sQueryString.indexOf("&", IndexBegin);
if(IndexEnd == -1)
IndexEnd = sQueryString.length;
var result = sQueryString.substring(IndexBegin, IndexEnd);
return result;
}var id = ParseQueryString(document.location);
//注意这里得到的id是string型的
{
var reg = new RegExp("(^|&|\\?)"+ name +"=([^&]*)(&|$)");
var r = this.match(reg);
if (r!=null) return unescape(r[2]); return null;
}var id = "showInfo.aspx?id=200701".getQueryString("id");
alert(id);var id = window.location.href.getQueryString("id");
if(id!=null) alert(id);
if(!sPrefix) sPrefix='';
if(!sStr) sStr=location.search;
if(sStr.length==0)return false;
sStr.replace(/([^\=\?\&]+)\=([^\&\=]+)/g,function($0,$1,$2){
eval(sPrefix+$1+'=$2');
});
} // end function fStrQryStr(sStr,sPrefix) //shawl.qiu code
function ParseQueryString(string)
{
var strQueryString = document.location.search;
var strSearchFor = string + "=";
var IndexBegin = strQueryString.indexOf(strSearchFor) + strSearchFor.length;
if(IndexBegin == -1)
return "";
var IndexEnd = strQueryString.indexOf("&", IndexBegin);
if(IndexEnd == -1)
IndexEnd = strQueryString.length;
var result = strQueryString.substring(IndexBegin, IndexEnd);
return result;
}这个用法就跟Request.QueryString差不多了
比如
var id = ParseQueryString("id");