谢谢 function a(){ alert(Array.apply(null,arguments)) alert(Array.apply(null,arguments)[0]) alert(arguments[0]) } a(33) Array.apply(null,arguments[0] 怎么不行啊?
function a() { alert(Array.apply(null,a.caller.arguments)) } function fun() { a(); }fun(1);这样怎么不行啊?
<script language="JavaScript"> <!-- function a() { alert(Array.prototype.slice.apply(a.caller.arguments)) } function fun() { a(); }fun(1); //--> </script>
直接用Array.apply会有问题 用Array.prototype.slice
function b(){ a(); } function a(){ var args=[]; var i,nLen=a.caller.arguments.length; for(i=0;i<nLen;i++){ args.push(a.caller.arguments[i]); } alert(args); }b(1,2,3);
function a(){
alert(Array.apply(null,arguments))
alert(Array.apply(null,arguments)[0])
alert(arguments[0])
}
a(33)
Array.apply(null,arguments[0] 怎么不行啊?
{
alert(Array.apply(null,a.caller.arguments))
}
function fun()
{
a();
}fun(1);这样怎么不行啊?
<script language="JavaScript">
<!--
function a()
{ alert(Array.prototype.slice.apply(a.caller.arguments))
}
function fun()
{
a();
}fun(1);
//-->
</script>
a();
}
function a(){
var args=[];
var i,nLen=a.caller.arguments.length;
for(i=0;i<nLen;i++){
args.push(a.caller.arguments[i]);
}
alert(args);
}b(1,2,3);