那就不用连接,整个连接式样的文字
可能式鼠标离开连接把事件传到div,执行了div的onmouseout
在连接里加onmouseout="event。cancelBubble()" 试一试

解决方案 »

  1.   

    <div class="mainSettingPopMenu" id="popupMenu" onMouseMove="OpenPopupMenu()" onmouseout="closePopupMenu();">
                            <ul>
                                <li>用戶設定</li>
                                <li>專案設定</li>
                               
                            </ul>
    搞定
      

  2.   

    <div class="mainSettingPopMenu" id="popupMenu" onMouseMove="OpenPopupMenu();" onmouseout="closePopupMenu();">
      

  3.   

    contains()鼠标当前移动到的对象是否在那个div里,注意兼容