怎样实现点击链接弹出文件下载框？

Question

 //文件下载
            string name = this.Request.QueryString["name"].ToString();
            string createPath = HttpContext.Current.Server.MapPath("~/Documents/HelpFile/" + name);
            if (name.Contains("/"))
            {
                name = name.Split('/')[1].ToString();
            }
            FileInfo DownloadFile = new FileInfo(createPath);
            Response.Clear();
            Response.ClearHeaders();
            Response.Buffer = false;
            Response.ContentType = "application/x-shockwave-flash";
            Response.AppendHeader("Content-Disposition", "attachment;filename=" + name);
            Response.AppendHeader("Content-Length", DownloadFile.Length.ToString());
            Response.WriteFile(DownloadFile.FullName);
            Response.Flush();
            Response.End();
跳到这个页面后再传参数过来就行了！

Answer 1

<%
Filename = "tesdt.txt"
Response.ContentType = "application/vnd.ms-Word"
Response.AddHeader "content-disposition", "attachment; filename=" & filename
%>