初学struts 的 小问题

Question

 警告: Unable to find 'seccess' forward.为什么老有这样的错误 转不到指定的界面
<forward name="seccess" path="/index.jsp"/>  xml里面的
return mapping.findForward("seccess");Action里面的    谢谢!!!!!!!!!   

Answer 1

检查一下你的web.xml中的配制是否正确..路径是否有问题.
如:
<servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
      <param-name>config</param-name>
      <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <init-param>
      <param-name>debug</param-name>
      <param-value>2</param-value>
    </init-param>
    <init-param>
      <param-name>application</param-name>
      <param-value>ApplicationResources</param-value>
    </init-param>
    <load-on-startup>2</load-on-startup>
  </servlet>

Answer 2

web.xml里面也没有问题  郁闷