如何在每月的10号让程序做某一件事

定时任务调度，你可以使用cron

java.util.Timer t = new Timer();t.shechde(new TaskA(), new Date(107,7,25,8,0,0), 1000*60*60*24);application.setAttribute("task", t);
--------------------------------
class TaskA() extends TimerTask{
  public void run(){
    Date date = new Date();
    if(date.getDate()==10){
      doSomething();
    }
  }}

jdring.非常好用！上网下个jdring.jar
下面是类似代码：
private static AlarmManager mgr = new AlarmManager();
private static AlarmEntry entry;
//AlarmManager.addAlarm(minute, hour, day of month, month, day of week, year,AlarmListener)
entry= mgr.addAlarm(-1 , -1 , new Integer(10), -1, -1, -1, new ExecuteJob());

new ExecuteJob())是你要执行的东西

windows操作系统自带一个"任务计划",可以把你的程序放在"任务计划"里,设定每月的10号启动运行程序。

Calender cal=Calender.getInstance();
int thisday=cal.get(Calender.DATE);
if(thisday==10)
{
.........
}

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN"
"http://www.springframework.org/dtd/spring-beans.dtd"><beans>
<bean id="exampleBusinessObject" class="com.dhcc.wms.quartz.Emmagee"/> <bean id="methodInvokingJobDetail" class="org.springframework.scheduling.quartz.MethodInvokingJobDetailFactoryBean">
<property name="targetObject"><ref bean="exampleBusinessObject"/></property>
<property name="targetMethod"><value>doIt</value></property>
<property name="concurrent"><value>false</value></property>
</bean> <bean id="cronTrigger" class="org.springframework.scheduling.quartz.CronTriggerBean">
<property name="jobDetail"><ref bean="methodInvokingJobDetail"/></property>
<property name="cronExpression"><value>0 0/2 12 * * ?</value></property>
</bean> <bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean">
<property name="triggers">
<list>
<ref local="cronTrigger"/>
</list>
</property>
</bean>
</beans>自己修改你要执行的类文件和时间属性就可以了

是个java应用程序,放在unix下运行的

超酷签名，点击这里和我直接沟通
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要么用定时线程，要不就通过系统配置实现，比如Unix里头的CronTab

quartz
声明一下，它不是Spring的
是一个独立的开源项目
上sourceForge看一下

jdring.非常好用！上网下个jdring.jar
下面是类似代码：
private static AlarmManager mgr = new AlarmManager();
private static AlarmEntry entry;
//AlarmManager.addAlarm(minute, hour, day of month, month, day of week, year,AlarmListener)
entry= mgr.addAlarm(-1 , -1 , new Integer(10), -1, -1, -1, new ExecuteJob());

new ExecuteJob())是你要执行的东西可是这段代码执行起来好像有点问题错误为:
Alarm.java:13: <identifier> expected
mgr.addAlarm(00,12,new Integer(10),-1,-1,-1,new AlarmListener(){
^
1 error
这是怎么回事啊,请各位大哥给点意见啊!!!谢谢!!!
我的完整的代码是:
package com.jalios.jdring;import com.jalios.jdring.*;public class Alarm{
//public static void main(String args[]){

//}private static AlarmManager mgr = new AlarmManager();
/s/AlarmEntry entry;mgr.addAlarm(00,12,-1,-1,-1,-1,new AlarmListener(){
public void handlnAlarm(AlarmEntry entry){
System.out.println("Lunch time !");
}
});
}

还有上面一段代码为:
package com.jalios.jdring;import java.util.TimerTask;
import java.util.Timer;
import java.util.*;
import com.jalios.jdring.*;public class timeTask{
public static void main(String args[]){
Timer t = new Timer();
t.shechde(new TaskA(), new Date(107,7,25,8,0,0), 1000*60*60*24);
application.setAttribute("task", t);
}
}
class TaskA extends TimerTask{
  public void run(){
    Date date = new Date();
    if(date.getDate()==10){
      System.out.println("It's time for lunch !!! ");
    }
  }
}错误为:
timeTask.java:11: cannot resolve symbol
symbol  : method shechde (com.jalios.jdring.TaskA,java.util.Date,int)
location: class java.util.Timer
                t.shechde(new TaskA(), new Date(107,7,25,8,0,0), 1000*60*60*24);
                 ^
timeTask.java:12: cannot resolve symbol
symbol  : variable application
location: class com.jalios.jdring.timeTask
                application.setAttribute("task", t);
                ^
Note: timeTask.java uses or overrides a deprecated API.
Note: Recompile with -deprecation for details.
2 errors执行起来有两个问题,请大家给点意见,谢谢!!!

Timer无法指定具体的时间执行任务。所以采用quartz是不错的选择。
下载个quartz.jar
cron表达式：每月的10号： 0 0 0 10 * ?
两个步骤：
1：编写你需要执行的任务：
SimpleQuartzJob.java:
public class SimpleQuartzJob implements Job {    public SimpleQuartzJob() {
    }    public void execute(JobExecutionContext context) throws JobExecutionException {
        System.out.println("In SimpleQuartzJob - executing its JOB at "
                + new Date() + " by " + context.getTrigger().getName());
    }
}2：设置cron表达式，run it：
CronTriggerRunner.java:import org.quartz.CronExpression;
import org.quartz.CronTrigger;
import org.quartz.JobDetail;
import org.quartz.Scheduler;
import org.quartz.SchedulerException;
import org.quartz.SchedulerFactory;
import org.quartz.impl.StdSchedulerFactory;/**
*/
public class CronTriggerRunner {    public void task() throws SchedulerException
    {
        // Initiate a Schedule Factory
        SchedulerFactory schedulerFactory = new StdSchedulerFactory();
        // Retrieve a scheduler from schedule factory
        Scheduler scheduler = schedulerFactory.getScheduler();

        // current time
        long ctime = System.currentTimeMillis();

        // Initiate JobDetail with job name, job group, and executable job class
        JobDetail jobDetail = new JobDetail("jobDetail1", "jobDetailGroup1", SimpleQuartzJob.class);
        // Initiate CronTrigger with its name and group name
        CronTrigger cronTrigger = new CronTrigger("cronTrigger", "triggerGroup1");
        try {
            // setup CronExpression
            CronExpression cexp = new CronExpression("0 0 0 10 * ?");
            // Assign the CronExpression to CronTrigger
            cronTrigger.setCronExpression(cexp);
        } catch (Exception e) {
            e.printStackTrace();
        }
        // schedule a job with JobDetail and Trigger
        scheduler.scheduleJob(jobDetail, cronTrigger);

        // start the scheduler
        scheduler.start();
    }

    public static void main (String args[])
    {
        try {
            CronTriggerRunner qRunner = new CronTriggerRunner();
            qRunner.task();
        } catch (Exception e)
        {
            e.printStackTrace();
        }
        System.out.println("is run!");
    }

}

junliu_0(驴子)d的解决方案最好，等linux下的solution

调试易

如何在每月的10号让程序做某一件事

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