请教如何在jsp页面将一个url地址的页面动态的包含近年来啊?
比如在a.jsp中动态包含http://www.baidu.com/s?wd=%BE%C8%C3%FC&oq=jiuming&f=3&rsp=0中的内容,参数值是动态变化的,用include不行,
向各位求解,先谢过
比如在a.jsp中动态包含http://www.baidu.com/s?wd=%BE%C8%C3%FC&oq=jiuming&f=3&rsp=0中的内容,参数值是动态变化的,用include不行,
向各位求解,先谢过
<body>
This is my JSP page. <br>
<jsp:include flush="true" page="http://127.0.0.1:8852"></jsp:include>
</body>
会在打开的网页上显示
This is my JSP page.
The requested resource (/test/http:/127.0.0.1:8852) is not available
我想将新申请的页面也包含进来,那该如何做呢?
请各位帮帮忙
<jsp:include flush="true" page="<%=path%>"></jsp:include>
简单。String pageContent = readUrl("http://www.baidu.com/s?wd=%BE%C8%C3%FC&amp;amp;oq=jiuming&amp;amp;f=3&amp;amp;rsp=0");public String readUrl(String urlString) {
URL url = new URL(urlString);
BufferedReader in = new BufferedReader(
new InputStreamReader(
url.openStream())); String inputLine;
String urlBuf = new StringBuffer(); while ((inputLine = in.readLine()) != null)
urlBuf.append(inputLine).append("\r\n"); in.close();
return urlBuf.toString();
}