怎么把String强制转换为int呢

Question

看看这样为什么错呢?
怎么改呢?
 int shuliang=(int )request.getParameter("shuliang");
报错是这样
inconvertible types
found   : java.lang.String
required: int
  int shuliang=(int )request.getParameter("shuliang");
                                         ^

Answer 1

Integer.parseInt(s)
可以把字符串转成整型

Answer 2

int shuliang=Integer.parseInt(request.getParameter("shuliang");)

Answer 3

int   i   =   Integer.valueOf(str).intValue();   
也可以的,baidu 上面到处都是的

Answer 4

这样写出错了
An error occurred at line: 42 in the jsp file: /shouji/chukutj.jsp
Generated servlet error:
/usr/java/jakarta-tomcat-5.0.28/work/Catalina/localhost/_/org/apache/jsp/shouji/chukutj_jsp.java:112: ')' expected
  int shuliang=Integer.parseInt(request.getParameter("shuliang");)
                                                                ^
An error occurred at line: 42 in the jsp file: /shouji/chukutj.jsp
Generated servlet error:
/usr/java/jakarta-tomcat-5.0.28/work/Catalina/localhost/_/org/apache/jsp/shouji/chukutj_jsp.java:112: illegal start of expression
  int shuliang=Integer.parseInt(request.getParameter("shuliang");)
                                                                 ^
2 errors

Answer 5

int shuliang=Integer.parseInt(request.getParameter("shuliang"));
不好意思呀。那个分号应该在最后了。哈

Answer 6

int shuliang=Integer.parseInt(request.getParameter("shuliang")；)你在吗分号都拷进去了

Answer 7

int shuliang=Integer.parseInt(request.getParameter("shuliang"))；

Answer 8

不是
int shuliang=Integer.parseInt(request.getParameter("shuliang");)应该是
int shuliang=Integer.parseInt(request.getParameter("shuliang"));