if(!schuid.equals(""))
{
sql="select * from usertab where userid='"+schuid+"'";
ResultSet urs=lgst.executeQuery(sql);
if(urs.next())
{
g=true;///21行;
}
}if(g)
{
session.setAttribute("srs",urs);
}
报错如下:
org.apache.jasper.JasperException: Unable to compile class for JSPAn error occurred at line: 11 in the jsp file: /biye/bank/search2.jsp
Generated servlet error:
C:\jakarta-tomcat-5.0.28\work\Catalina\localhost\_\org\apache\jsp\biye\bank\search2_jsp.java:109: cannot resolve symbol
symbol : variable urs
location: class org.apache.jsp.biye.bank.search2_jsp
session.setAttribute("srs",urs);我把session.setAttribute("srs",urs);放在换21行就没问题?为什么呀??
{
sql="select * from usertab where userid='"+schuid+"'";
ResultSet urs=lgst.executeQuery(sql);
if(urs.next())
{
g=true;///21行;
}
}if(g)
{
session.setAttribute("srs",urs);
}
报错如下:
org.apache.jasper.JasperException: Unable to compile class for JSPAn error occurred at line: 11 in the jsp file: /biye/bank/search2.jsp
Generated servlet error:
C:\jakarta-tomcat-5.0.28\work\Catalina\localhost\_\org\apache\jsp\biye\bank\search2_jsp.java:109: cannot resolve symbol
symbol : variable urs
location: class org.apache.jsp.biye.bank.search2_jsp
session.setAttribute("srs",urs);我把session.setAttribute("srs",urs);放在换21行就没问题?为什么呀??
解决方案 »
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可以这样boolean g = false;if(!schuid.equals("")){内容不变}if(g){内容不变}
ResultSet urs=lgst.executeQuery(sql);把这两句也单独提出来
sql="select * from usertab where userid='"+schuid+"'";
ResultSet urs=lgst.executeQuery(sql);
后,第一个if貌似没有意义了,还是把第2个if嵌入第1个if吧if(!schuid.equals(""))
{
sql="select * from usertab where userid='"+schuid+"'";
ResultSet urs=lgst.executeQuery(sql);
if(urs.next())
{
g=true;///21行;
}
if(g)
{
session.setAttribute("srs",urs);
}
}