怎么样消除重复的数组

Question

我现在将65个单词（有重复）分别定义给一个65位的一维数组。现在从中随机取出24个，怎样保证24个中没有重复取得？

Answer 1

String s[65]={};
String sk[24];//要得的数组
for(int i=0;i<s.length;i++)
{ 
for(int j=0;j<s.length;j++)
if (!s[i].equals(s[j])){
sk[]=s[i];
}else{
break;
}
}

Answer 2

String[] array65={"0","1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26","27","28","29","30","31","32","33","34","35","36","37","38","39","40","41","42","43","44","45","46","47","48","49","50","51","52","53","54","55","56","57","58","59","60","61","62","63","64"};
// array65初始化 array65 = {,,,,,,.....};
String[] array24=new String[24];
int count = 0;
boolean flag = false;
while(count<24){
System.out.println(count);
int random = (int)(Math.random()*65);

for(int j=0;j<array24.length;j++){
if(array65[random].equals(array24[j])){
flag = true;
continue;
}
}
if(!flag){
array24[count]=array65[random];
System.out.print(array24[count]+",");
count++;
}

}
效率级差,期待好点的算法

Answer 3

Random r = new Random();
ArrayList<String> list = new ArrayList<String>(25);
String[] array65={"0","1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20","21","22","23","24","25","26","27","28","29","30","31","32","33","34","35","36","37","38","39","40","41","42","43","44","45","46","47","48","49","50","51","52","53","54","55","56","57","58","59","60","61","62","63","64"};
while (list.size() < 24) {
  int nIdx = r.nextInt(65);
  if (list.indexOf(array65[nIdx]) < 0) {
    list.add(array65[nIdx]);
  }
}
String[] results =list.toArray(new String[list.size()]) ;
System.out.println(Arrays.asList(results));