web中参数传递的问题

Question

&SIGN=
WVgdx6yGA4toVY1jQMcbVpI7qWQQn9PYtWAGW+JQwkBN8VSDZutBPOuf3emNKz/cxFKql5xKLvtmzEdh8DZh23KwPX65uX8JKeJCgmwqQaS3CONg78KXwC3pyQo3lr3V2gs2Yp72gYcUqirpOiHJtnmFgnwq2YT+yuzGeNKxnnY=
如上在url中传递一个参数
接受后变成WVgdx6yGA4toVY1jQMcbVpI7qWQQn9PYtWAGW JQwkBN8VSDZutBPOuf3emNKz/cxFKql5xKLvtmzEdh8DZh23KwPX65uX8JKeJCgmwqQaS3CONg78KXwC3pyQo3lr3V2gs2Yp72gYcUqirpOiHJtnmFgnwq2YT yuzGeNKxnnY=
里面的+号不见了..请问这怎么回事啊?

Answer 1

如果yuzGeNKxnnY是参数名的话，请把前面的+，写成&

Answer 2

在传参数之前把参数转下码
<%
  String param=java.net.URLEncoder.encode("aaaaa+aaa+aa+++aaa");
%><a href="a.jsp?param=<%=param%>">超连接传参数带+号</a>

Answer 3

&SIGN=
WVgdx6yGA4toVY1jQMcbVpI7qWQQn9PYtWAGW+JQwkBN8VSDZutBPOuf3emNKz/cxFKql5xKLvtmzEdh8DZh23KwPX65uX8JKeJCgmwqQaS3CONg78KXwC3pyQo3lr3V2gs2Yp72gYcUqirpOiHJtnmFgnwq2YT+yuzGeNKxnnY=
这个已经是一个串的urldecoder编码了

Answer 4

URLEncoder.encode(...)处理下就好了

Answer 5

URLEncoder.encode(...)处理下就好了