检查web.xml中servlet的配置路径是否正确

解决方案 »

  1.   

    web.xml文件配置出错,所以找不到这个Servlet的Location
    请楼主把web.xml文件贴出来。到底对错就知道了。
      

  2.   

    不会把,也不会打出 E:\Shopping.......
      

  3.   

    XML如下````<?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
      <display-name>WebModule1</display-name>
      <jsp-config>
        <taglib>
          <taglib-uri>/WEB-INF/struts-bean.tld</taglib-uri>
          <taglib-location>/WEB-INF/struts-bean.tld</taglib-location>
        </taglib>
        <taglib>
          <taglib-uri>/WEB-INF/struts-html.tld</taglib-uri>
          <taglib-location>/WEB-INF/struts-html.tld</taglib-location>
        </taglib>
        <taglib>
          <taglib-uri>/WEB-INF/struts-logic.tld</taglib-uri>
          <taglib-location>/WEB-INF/struts-logic.tld</taglib-location>
        </taglib>
        <taglib>
          <taglib-uri>/WEB-INF/struts-template.tld</taglib-uri>
          <taglib-location>/WEB-INF/struts-template.tld</taglib-location>
        </taglib>
        <taglib>
          <taglib-uri>/WEB-INF/struts-tiles.tld</taglib-uri>
          <taglib-location>/WEB-INF/struts-tiles.tld</taglib-location>
        </taglib>
        <taglib>
          <taglib-uri>/WEB-INF/struts-nested.tld</taglib-uri>
          <taglib-location>/WEB-INF/struts-nested.tld</taglib-location>
        </taglib>
      </jsp-config>
      <servlet>
        <servlet-name>action</servlet-name>
        <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
        <init-param>
          <param-name>config</param-name>
          <param-value>/WEB-INF/struts-config.xml</param-value>
        </init-param>
        <init-param>
          <param-name>debug</param-name>
          <param-value>2</param-value>
        </init-param>
        <init-param>
          <param-name>application</param-name>
          <param-value>ApplicationResources</param-value>
        </init-param>
        <load-on-startup>2</load-on-startup>
      </servlet>
      <servlet-mapping>
        <servlet-name>action</servlet-name>
        <url-pattern>*.do</url-pattern>
      </servlet-mapping>
      <servlet>
        <servlet-name>loginservlet</servlet-name>
        <servlet-class>shopping.LoginServlet</servlet-class>
      </servlet>
      <servlet-mapping>
        <servlet-name>loginservlet</servlet-name>
        <url-pattern>/loginservlet</url-pattern>
      </servlet-mapping>
    </web-app>
      

  4.   

    <servlet>
        <servlet-name>loginservlet</servlet-name>
        <servlet-class>shopping.LoginServlet</servlet-class>
    </servlet>这里给了调用LoginServlet类的别名,页面中调用只要用别名就可以了。不用在乎类在那个包下,是什么名称。
      

  5.   

    method="post"
    ^^^^^^^^^^^^^doGet(HttpServletRequest request, HttpServletResponse response)
    ^^^^^"post"=="get"???????
      

  6.   

    <form name="form1" method="post" action="LoginServlet">
    你都method  post  怎么又在Get下面写啊...
      

  7.   

    http://ent.yuyao.com/Board.asp?BoardID=2这个网址看一下吧,这里面有详细的文章及解说,可能有你所需要的答案,包括工具|办 |系统|图形|网站建设|网络编程|软件|数据库|多媒体|安全 等