public class Dcucardlib implements java.io.Serializable { private DcucardlibId id;
private Long imPower;
private Byte isSended;
}public class DcucardlibId implements java.io.Serializable { private Long dcuId;
private Cardlib cardlib = new Cardlib();
}Dcucardlib.hbm.xml
<hibernate-mapping>
<class name="com.dig.pojo.Dcucardlib" table="DCUCARDLIB" schema="dbo" catalog="DCU32">
<composite-id name="id" class="com.dig.pojo.DcucardlibId">
<key-property name="dcuId" type="java.lang.Long">
<column name="DcuID" />
</key-property>
<key-many-to-one name="cardlib" class="com.dig.pojo.Cardlib">
<column name="CardNo" />
</key-many-to-one>
</composite-id>
<property name="imPower" type="java.lang.Long">
<column name="ImPower" />
</property>
<property name="isSended" type="java.lang.Byte">
<column name="is_Sended" not-null="true" />
</property>
</class>
</hibernate-mapping>public class Cardlib implements java.io.Serializable { private Long cardNo;
private Long id;
private Byte isUse;
private String explain;
private Integer batchNo;
private Set dcucardlibs = new HashSet(0);
private String userName;
}Cardlib.hbm.xml
<hibernate-mapping>
<class name="com.dig.pojo.Cardlib" table="CARDLIB" schema="dbo" catalog="DCU32">
<id name="cardNo" type="java.lang.Long">
<column name="CardNo" />
</id>
<property name="id" type="java.lang.Long" update="false" insert="false">
<column name="ID" not-null="true" />
</property>
<property name="isUse" type="java.lang.Byte">
<column name="IsUse" />
</property>
<property name="explain" type="java.lang.String">
<column name="Explain" length="100" />
</property>
<property name="batchNo" type="java.lang.Integer">
<column name="BatchNo" />
</property>
<set name="dcucardlibs" inverse="true" cascade="all">
<key>
<column name="CardNo" not-null="true" />
</key>
<one-to-many class="com.dig.pojo.Dcucardlib" />
</set>
</class>
</hibernate-mapping>我现在需要通过cardNo的值把dcuId查询出来,返回的是List。初学,在此请教了,还望不吝赐教!在线等,急!!!
private Long imPower;
private Byte isSended;
}public class DcucardlibId implements java.io.Serializable { private Long dcuId;
private Cardlib cardlib = new Cardlib();
}Dcucardlib.hbm.xml
<hibernate-mapping>
<class name="com.dig.pojo.Dcucardlib" table="DCUCARDLIB" schema="dbo" catalog="DCU32">
<composite-id name="id" class="com.dig.pojo.DcucardlibId">
<key-property name="dcuId" type="java.lang.Long">
<column name="DcuID" />
</key-property>
<key-many-to-one name="cardlib" class="com.dig.pojo.Cardlib">
<column name="CardNo" />
</key-many-to-one>
</composite-id>
<property name="imPower" type="java.lang.Long">
<column name="ImPower" />
</property>
<property name="isSended" type="java.lang.Byte">
<column name="is_Sended" not-null="true" />
</property>
</class>
</hibernate-mapping>public class Cardlib implements java.io.Serializable { private Long cardNo;
private Long id;
private Byte isUse;
private String explain;
private Integer batchNo;
private Set dcucardlibs = new HashSet(0);
private String userName;
}Cardlib.hbm.xml
<hibernate-mapping>
<class name="com.dig.pojo.Cardlib" table="CARDLIB" schema="dbo" catalog="DCU32">
<id name="cardNo" type="java.lang.Long">
<column name="CardNo" />
</id>
<property name="id" type="java.lang.Long" update="false" insert="false">
<column name="ID" not-null="true" />
</property>
<property name="isUse" type="java.lang.Byte">
<column name="IsUse" />
</property>
<property name="explain" type="java.lang.String">
<column name="Explain" length="100" />
</property>
<property name="batchNo" type="java.lang.Integer">
<column name="BatchNo" />
</property>
<set name="dcucardlibs" inverse="true" cascade="all">
<key>
<column name="CardNo" not-null="true" />
</key>
<one-to-many class="com.dig.pojo.Dcucardlib" />
</set>
</class>
</hibernate-mapping>我现在需要通过cardNo的值把dcuId查询出来,返回的是List。初学,在此请教了,还望不吝赐教!在线等,急!!!
解决方案 »
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