jsp中如何对url后面带的参数进行加密进行解密，比如select.jsp?id=111&bb=444 我要对这后面的url进行加密

Question

jsp中如何对url后面带的参数进行加密进行解密，比如select.jsp?id=111&bb=444 我要对这后面的url进行加密然后在程序select.jsp中要对这加密后的数据进行解密回来，要能够正确知道参数值，加密成别的字符乱码，为的是不让别人知道我参数值各位有什么好的办法

Answer 1

这个……这个好象你自己随便写一个加密解密的类就行了撒
算法只要自己知道就行了，也不用太复杂…………
比如说，把每个字母和数字都用编号代替，把1变成ON1,2变成TW2…………
  这个规则自己清楚就行了
  解密的时候三位一组，还原回来就行了

Answer 2

http://pagead2.googlesyndication.com/pagead/iclk?sa=l&ai=BsGmnkD0mRbe0Ns_24QHi7rhtlcflHeOHxa8BwI23AdCGAxADGAMgt8iUAigEMAA4AEDsEFD7vNSMA6oBCjIxNjM0MzgyODmyARJjb21tdW5pdHkuY3Nkbi5uZXS6AQk3Mjh4OTBfYXPIAQHaAURodHRwOi8vY29tbXVuaXR5LmNzZG4ubmV0L0V4cGVydC9Gb3J1bUxpc3QuYXNwP3R5cGVudW09MSZyb29taWQ9NTQwOcgCseVW&num=3&adurl=http://www.altova.com/ref/%3Fs%3Dgoogleaw2%26q%3Dservlet&client=ca-pub-1076724771190722&nm=11
这是google.com广告上的链接,我想问一问这些乱码,是怎么加密的,这点后,又要如何解密

Answer 3

试试吧，刚刚拿记事本写的，我家里没java，没办法测试-_|||||||
不管成功不成功，反正思路差不多
public class Security {
    String mapSting[] = {"ZE","ON","TW","TH","FO",
       "FI","SI","SE","EI","NI",
       "BA","BB","BC","BD","BE",
       "BF","B1","B2","B3","B4",
       "B5","B6","B7","B8","B9",
       "B0","Q1","R1","SK","3T",
       "YU","CV","PW","QX","HY",
       "CZ",
       "TY","TU","SA","SB","SS",
       "UI","VE","ZR","HR","WO",
       "LA","E8","3K","0R","4L",
       "3N","56","98","V9","6M",
       "6U","3J","Y4","67","ML",
       "ZZ"
      };    char mapChar[] = {'0','1','2','3','4',
    '5','6','7','8','9',
    'A','B','C','D','E',
    'F','G','H','I','J',
    'K','L','M','N','O',
    'P','Q','R','S','T',
    'U','V','W','X','Y',
    'Z',
    'a','b','c','d','e',
    'f','g','h','i','j',
    'k','l','m','n','o',
    'p','q','r','s','t',
    'u','v','w','x','y',
    'z'
   };    //这个是用来加密的
    public String getEncryption(String str) {
char[] ch = str.toCharArray();
StringBuilder sb = new StringBuilder();
         for(int i = 0;i<str.length();i++) {
    for(int j = 0;j<mapChar.length();j++) {
if(ch[i] == mapChar[j]) {
    sb.append(mapString[j]);
}
    }
        }
return sb.toString();
    }    //这个是解密的
    public String getDecryption(String str) {
StringBuilder sb = new StringBuilder();
for(int i = 0;i<str.length();i += 2) {
    for(int j = 0;j<mapString.length();j++) {
if(str.substring(i,i+2).equals(mapString[j])) {
    sb.append(mapChar[j]);
}
    }
}
return sb.toString();
    }
}

Answer 4

也可以尝试一下把提交方式改为post, get方法都是明文，post系统会自动加密

Answer 5

做成这样的：
select.jsp?param=18741s87cd3461e123451cfe23516e796d
解密后再提取真正的参数。