菜鸟求助。。。。。。。。 晕了。 找不到原因了。。。。初始化的时候出现异常！

Question

/// Formbean
package com;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionErrors;
import org.apache.struts.action.ActionFormBean;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse; class LoginActiondoForm extends ActionForm
{
 String userName;
 String passWord;

public void setName(String userName,String passWord)
{
this.userName = userName;
this.passWord = passWord;
}  public String getPassword()
{
return passWord;
}
public String getName()
{
return userName;
}
}
////action
package com;
import org.apache.struts.action.*;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.action.ActionForward;import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletException;public class LoginActiondo extends Action
{

   public ActionForward execute(ActionMapping mapping,ActionForm form,HttpServletRequest request,HttpServletResponse response)
   {
    String userName = ((LoginActiondoForm)form).getName();
    String passWord = ((LoginActiondoForm)form).getPassword();
   if(userName.equals("admin") || passWord.equals("1234"))
    {
      return mapping.findForward("succes");
      
    }
    else
    {
    return mapping.findForward("Erro");
    }
   }
}
/// Stuct-config
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE struts-config PUBLIC
          "-//Apache Software Foundation//DTD Struts Configuration 1.1//EN"
          "http://struts.apache.org/dtds/struts-config_1_1.dtd">
<struts-config>
  <form-beans>
      <form-bean name="loginform" type="com.LoginActiondoForm"/>
      <form-bean name="createBook" type ="com.bookForm" />
  </form-beans>
    <action-mappings>
      <action path="/login" name="loginform" input="/login.jsp" type="com.LoginActiondo">
        <forward name="success" path="/welcome.jsp"/>
       <forward name="Erro" path="/Erro.jsp"/>
       </action>
       <action path="/CreateBookAction" name="createBook" scope="request" input="/CreateBook.jsp" type="com.CreateBookAction" >
       <forward name="OK" path="/Erro.jsp" />
       </action>
  </action-mappings>
</struts-config>
/////下面是出现的异常信息！
javax.servlet.ServletException: Exception creating bean of class com.LoginActiondoForm: {1}
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:825)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:758)
org.apache.jsp.login_jsp._jspService(login_jsp.java:118)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause javax.servlet.jsp.JspException: Exception creating bean of class com.LoginActiondoForm: {1}
org.apache.struts.taglib.html.FormTag.doStartTag(FormTag.java:644)
org.apache.jsp.login_jsp._jspx_meth_html_form_0(login_jsp.java:135)
org.apache.jsp.login_jsp._jspService(login_jsp.java:87)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.0.28 logs.

Answer 1

ActionForm是一个符合JavaBean规范的类，所有的属性都应满足get和set对应。你的userName,passWord 都要有get/set方法

Answer 2

public void setName(String userName)
{
this.userName = userName;
//this.passWord = passWord;
} 
    public String getName()
{
return userName;
}

    public void setPassword(String passWord)
    {
     this.passWord = passWord;
    }
public String getPassword()
{
return passWord;
}
我改成这样了。还是出现同样的问题

Answer 3

楼主能说一下，改正后出现什么错误了吗？？？
另外if(userName.equals("admin") || passWord.equals("1234"))
应该改成if(userName.equals("admin") ＆＆ passWord.equals("1234"))
你判断的是两个条件都满足才成功，不能用逻辑或||应该用＆＆符

Answer 4

public void setUserName(String userName)
{
this.userName = userName;
//this.passWord = passWord;
} 
    public String getUserName()
{
return userName;
}

    public void setPassWord(String passWord)
    {
     this.passWord = passWord;
    }
public String getPassWord()
{
return passWord;
}

Answer 5

message description The server encountered an internal error () that prevented it from fulfilling this request.exception javax.servlet.ServletException: Exception creating bean of class com.LoginActiondoForm: {1}
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:825)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:758)
org.apache.jsp.login_jsp._jspService(login_jsp.java:83)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause javax.servlet.jsp.JspException: Exception creating bean of class com.LoginActiondoForm: {1}
org.apache.struts.taglib.html.FormTag.doStartTag(FormTag.java:644)
org.apache.jsp.login_jsp._jspx_meth_html_form_0(login_jsp.java:184)
org.apache.jsp.login_jsp._jspx_meth_html_html_0(login_jsp.java:123)
org.apache.jsp.login_jsp._jspService(login_jsp.java:74)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802还是和上面一样的错误

Answer 6

public class LoginActiondoForm extends ActionForm
{
private String userName;
private String passWord;

Answer 7

不行改了还是出现在这个问题。
private String userName;
private String passWord;

Answer 8

package com;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionErrors;
import org.apache.struts.action.ActionFormBean;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse; class LoginActiondoForm extends ActionForm
{
private String userName;
private String passWord;

public void setUserName(String userName)
{
this.userName = userName;
//this.passWord = passWord;
} 
    public String getUserName()
{
return this.userName;
}

    public void setPassWord(String passWord)
    {
     this.passWord = passWord;
    }
public String getPassword()
{
return this.passWord;
}}

Answer 9

偶不是用escplis 也不是用的是 ant 。偶用tomcat加。jcreat 
编译以后我是放到那个目录里的。

Answer 10

class LoginActiondoForm extends ActionForm 前加public

Answer 11

你的LoginActionForm类的访问权限是包访问权限,设置成public试一下吧.

Answer 12

class LoginActiondoForm extends ActionForm 前加public

Answer 13

用jbuilder吧，formbean自动生成，不费你一点儿神^-^