程序代码如下:
<%@ page contentType="text/html;charset=gb2312"%>
<%@ page import="java.lang.*,java.io.*,java.sql.*,java.util.*"%>
<html>
<body>
<%Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver").newInstance();
String url="jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=infosite";
String user="sa";
string password="sa";
Connection conn=null;
conn=DriverManager.getConnection(url,user,passwod);
Statement stmt=conn.createStatement();
String sql="Select * from news";
ResultSet rs=stmt.executQuery(sql);
while(rs.next()) {%>
您的第一个字段内容为:<%=rs.getString(1)%>
您的第二个字段内容为:<%=rs.getString(2)%>
<%}%>
<%out.print("数据库操作成功,恭喜你");%>
<%rs.close();
stmt.close();
conn.close();%>
</body></html>
错误提示如下:HTTP Status 500 - --------------------------------------------------------------------------------type Exception reportmessage description The server encountered an internal error () that prevented it from fulfilling this request.exception org.apache.jasper.JasperException: Unable to compile class for JSPAn error occurred at line: 5 in the jsp file: /conn1.jsp
Generated servlet error:
string cannot be resolved to a typeAn error occurred at line: 5 in the jsp file: /conn1.jsp
Generated servlet error:
passwod cannot be resolvedAn error occurred at line: 5 in the jsp file: /conn1.jsp
Generated servlet error:
The method executQuery(String) is undefined for the type Statement
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:328)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:409)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:288)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:267)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:255)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:563)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:293)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.12 logs.
<%@ page contentType="text/html;charset=gb2312"%>
<%@ page import="java.lang.*,java.io.*,java.sql.*,java.util.*"%>
<html>
<body>
<%Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver").newInstance();
String url="jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=infosite";
String user="sa";
string password="sa";
Connection conn=null;
conn=DriverManager.getConnection(url,user,passwod);
Statement stmt=conn.createStatement();
String sql="Select * from news";
ResultSet rs=stmt.executQuery(sql);
while(rs.next()) {%>
您的第一个字段内容为:<%=rs.getString(1)%>
您的第二个字段内容为:<%=rs.getString(2)%>
<%}%>
<%out.print("数据库操作成功,恭喜你");%>
<%rs.close();
stmt.close();
conn.close();%>
</body></html>
错误提示如下:HTTP Status 500 - --------------------------------------------------------------------------------type Exception reportmessage description The server encountered an internal error () that prevented it from fulfilling this request.exception org.apache.jasper.JasperException: Unable to compile class for JSPAn error occurred at line: 5 in the jsp file: /conn1.jsp
Generated servlet error:
string cannot be resolved to a typeAn error occurred at line: 5 in the jsp file: /conn1.jsp
Generated servlet error:
passwod cannot be resolvedAn error occurred at line: 5 in the jsp file: /conn1.jsp
Generated servlet error:
The method executQuery(String) is undefined for the type Statement
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:328)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:409)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:288)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:267)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:255)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:563)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:293)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.12 logs.
就是JDBC
你得在你的JB里导进来
Connection conn=null;
conn=DriverManager.getConnection(url,user,passwod);
------------------------------
你前后2次password写错了,改对就好了
------------
这个也写错了
对后台的操作一般不放在前台页面进行处理,代码看起来太乱了。
其次,就是没有对异常的处理!ResultSet rs=stmt.executQuery(sql);
好像对着呢吧粗无应该就是 password != passwod 吧
楼主仔细检查
conn=DriverManager.getConnection(url,user,passwod);
这句话
写错了,应该是ResultSet rs=stmt.executeQuery(sql);少写了一个e
<%@ page import="java.sql.*"%>
<html>
<body>
<%
String url="jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=infosite";
String user="sa";
String password="wsfljm11";
Connection conn=null;
Statement stmt=null;
ResultSet rs=null;
String sql=null;
try{
Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver").newInstance();
conn=DriverManager.getConnection(url,user,password);
stmt=conn.createStatement();
sql="Select * from news";
rs=stmt.executeQuery(sql);
while(rs.next())
{
%>
您的第一个字段内容为:<%=rs.getString(1)%>
您的第二个字段内容为:<%=rs.getString(2)%>
<%
}
out.print("数据库操作成功,恭喜你");
}
catch(Exception e)
{
out.println("Exception:"+e);
}
rs.close();
stmt.close();
conn.close();
%>
</body>
</html>
String url="jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=infosite";
infosite是你数据库的名字,要核对清楚String user="sa";
string password="sa";数据库的帐号和密码,这些都没问题了应该就ok了
2000系统下,可以将Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver").newInstance();
String url="jdbc:microsoft:sqlserver://localhost:1433;DatabaseName=infosite";
这两句换成
Class.forName("sun.jdbc.odbc.JdbcOdbcDriver").newInstance();
String url = "jdbc:odbc:infosite";并且要设置数据源
不知道这样讲你明白了没有,要是不清楚可以加我(qq:81357848)我帮你解答
谢谢各位老大尤其是:wsk_228(qing_feng)和小猪,谢谢你们的细心教导!