List kqList = YgkqDAO.find("yg001");
String[][] str = null;
for(int i=0;i <kqList.size();i++){
YgkqBean ygkqbean=(YgkqBean)kqList.get(i);
str[i][0] = ygkqbean.getId;
str[i][1] = ygkqbean.getName;
str[i][2] = ygkqbean.getCode;
...
}
应该是这样把 LZ的问题说明的不太清楚
String[][] str = null;
for(int i=0;i <kqList.size();i++){
YgkqBean ygkqbean=(YgkqBean)kqList.get(i);
str[i][0] = ygkqbean.getId;
str[i][1] = ygkqbean.getName;
str[i][2] = ygkqbean.getCode;
...
}
应该是这样把 LZ的问题说明的不太清楚
但是
str[i][0] = ygkqbean.getId;
str[i][1] = ygkqbean.getName;
str[i][2] = ygkqbean.getCode;
这种赋值只是行的动态赋值啊,我想列也动态赋值,不知道有什么方法没有啊~~先谢谢了
String[][] str = null;
for(int i=0;i <kqList.size();i++){
YgkqBean ygkqbean=(YgkqBean)kqList.get(i);
for(int j=0;j<kqList.size();j++){
str[i][j] = ygkqbean.get(j);
}
}
如果你的list里面保存的只一种结构就只有使用一楼的方法