【１００分】Java中如何获取一个URL地址的网页的Html代码

Question

见如下文档：
http://www.itfuture.org/show.jsp?cid=146
一定要给分呀！
以后有问题可以到
  http://www.itfuture.org/liuy
  上提问有问必答！！

Answer 1

很久以前写玩的，没仔细看，有问题在问我。/**
 * This client send 1 byte 1000 times.
 */
import java.io.*;
import java.net.*;/**
 * @author Chen Jay
 */
public class TCPClient { public static void main(String[] args) {
// TODO Auto-generated method stub
Socket client;
int count = 0;
long start;
long end;
try {
if (args.length != 2) {
System.out.println("Usage: java TCPClient <host> [port]");
return;
}
start = System.currentTimeMillis();
while (count < 1000) {
client = new Socket(args[0], Integer.parseInt(args[1]));
DataOutputStream out = new DataOutputStream(client
.getOutputStream());
client.getInputStream();
out.write("a".getBytes());
client.close();
count++;
}
end = System.currentTimeMillis();
System.out.println("One loops cost:"
+ (double) ((end - start) / 1000) + "ms");
} catch (UnknownHostException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}}

Answer 2

使用jndi,给个例子，使用ejb，只写一个SessionBeanimport javax.naming.*;
import javax.ejb.*;
import java.net.*;
import java.io.*;public class HTMLReaderBean implements SessionBean {
 
  public StringBuffer getContents() throws HTTPResponseException {     Context context;
     URL url;
     StringBuffer buffer;
     String line;
     int responseCode;
     HttpURLConnection connection;
     InputStream input;
     BufferedReader dataInput;
 
     try {
        context = new InitialContext();
        url = (URL)context.lookup("java:comp/env/url/MyURL");  
        connection = (HttpURLConnection)url.openConnection();
        responseCode = connection.getResponseCode();
     } catch (Exception ex) {
         throw new EJBException(ex.getMessage());
     }     if (responseCode != HttpURLConnection.HTTP_OK) {
        throw new HTTPResponseException("HTTP response code: " + 
           String.valueOf(responseCode));
     }     try {
        buffer = new StringBuffer();
        input = connection.getInputStream();
        dataInput = new BufferedReader(new InputStreamReader(input));
        while ((line = dataInput.readLine()) != null) {
           buffer.append(line);
           buffer.append('\n');
        }  
     } catch (Exception ex) {
         throw new EJBException(ex.getMessage());
     }     return buffer;  } // getContents()   public HTMLReaderBean() {}
   public void ejbCreate() {}
   public void ejbRemove() {}
   public void ejbActivate() {}
   public void ejbPassivate() {}
   public void setSessionContext(SessionContext sc) {}} 

Answer 3

用URLConnection 最方便，参考以下代码：
URL url = new URL("http://www.abc.com/abc.html");
URLConnection conn = url.openConnection();
InputStream inStream = conn.getInputStream();FileOutputStream fs = new FileOutputStream(outputFilename);
byte[] buffer = new byte[1024];
int length=0;
int byteread = 0;
int bytesum = 0;
while ((byteread = inStream.read(buffer)) != -1) {
    bytesum += byteread;
    fs.write(buffer, 0, byteread);
}
fs.close();

Answer 4

strHtml是网页的Html代码 URLConnection uc = new URL(url).openConnection();
uc.setConnectTimeout(10000);
uc.setDoOutput(true);

InputStream in = new BufferedInputStream(uc.getInputStream());
Reader rd = new InputStreamReader(in);
int c = 0;
StringBuffer temp = new StringBuffer();
while ((c = rd.read()) != -1) {
temp.append((char) c);
}
in.close();

strHtml = temp.toString(); //strHtml请求网页代码

Answer 5

通过ajax获取之后，然后通过隐藏文本通过form表单最后提交给java类哦
如下： <script type="text/javascript">var xmlHttp;function createXMLHttpRequest() {    if (window.ActiveXObject) {        xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");    }    else if (window.XMLHttpRequest) {        xmlHttp = new XMLHttpRequest();    }}function startRequest() {
     var name= document.bianji.name.value;
    createXMLHttpRequest(); 
    xmlHttp.open("GET", "./newmessage.html", true);
    xmlHttp.setRequestHeader("Content-Type","GBK");
    xmlHttp.onreadystatechange = handleStateChange;
    xmlHttp.send(null);
    xmlhttp.setRequestHeader("If-Modified-Since","0");   
}
function handleStateChange() {    if(xmlHttp.readyState == 4) {
    
          
        if(xmlHttp.status == 200) {      
           document.bianji.message.value = xmlHttp.responseText;
        }    }}</script>
<form action="类名" name="bianji" method="POST"> 
 
    <table width=800>
  <tr> 
  <td> <input type="hidden"  name="message" value=""/>
                 <input type="submit"  value="提交 "   onclick="startRequest();"/>
  </td>
  </tr>        
    </table>        
 </form>