出错信息如下:
type Exception reportmessage description The server encountered an internal error () that prevented it from fulfilling this request.exception javax.servlet.ServletException: abc.Test.save(Ljava/lang/String;Ljava/lang/String;)V
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:682)
org.apache.jsp.registry2_jsp._jspService(registry2_jsp.java:96)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:552)
org.apache.jsp.registry1_jsp._jspService(registry1_jsp.java:75)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
tw.com.javaworld.CH11.HelloFilter.doFilter(Unknown Source)
root cause java.lang.NoSuchMethodError: abc.Test.save(Ljava/lang/String;Ljava/lang/String;)V
org.apache.jsp.registry2_jsp._jspService(registry2_jsp.java:76)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:552)
org.apache.jsp.registry1_jsp._jspService(registry1_jsp.java:75)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
tw.com.javaworld.CH11.HelloFilter.doFilter(Unknown Source)
note The full stack trace of the root cause is available in the Tomcat logs.
type Exception reportmessage description The server encountered an internal error () that prevented it from fulfilling this request.exception javax.servlet.ServletException: abc.Test.save(Ljava/lang/String;Ljava/lang/String;)V
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:682)
org.apache.jsp.registry2_jsp._jspService(registry2_jsp.java:96)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:552)
org.apache.jsp.registry1_jsp._jspService(registry1_jsp.java:75)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
tw.com.javaworld.CH11.HelloFilter.doFilter(Unknown Source)
root cause java.lang.NoSuchMethodError: abc.Test.save(Ljava/lang/String;Ljava/lang/String;)V
org.apache.jsp.registry2_jsp._jspService(registry2_jsp.java:76)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:552)
org.apache.jsp.registry1_jsp._jspService(registry1_jsp.java:75)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
tw.com.javaworld.CH11.HelloFilter.doFilter(Unknown Source)
note The full stack trace of the root cause is available in the Tomcat logs.
应该是这句错了呀.少了个字段
我把完整的JSP贴出来了,2个参数都是String的,而且save方法我写的是对的
<%@ page import="java.sql.*" %>
<%@ page contentType="text/html;charset=GB2312" %>
<html>
<head>
<title>registry2</title>
</head>
<body>
<form method=post action="registry2.jsp">
<input name="user_password" type="password">
<input name="confim" type="password">
</form>
<%
String user_password = request.getParameter("user_password");
String confim = request.getParameter("confim");
String name = request.getParameter("name");
if(user_password==confim) {
%>
<jsp:useBean id = "test" scope = "request" class = "abc.Test"/>
<%
test.save(name,user_password);
%>
<jsp:forward page="registry3.jsp"/>
<%
}
else out.println("输入密码和确认密码不同,重新输入.");
%>
</body>
</html>
<HTML>
<HEAD>
<TITLE>registry1</TITLE>
</HEAD>
<BODY>
<FORM METHOD=POST ACTION="registry1.jsp">
姓名:<input name="name" type="text">
<input type="submit" value="提交">
<jsp:useBeanid="test"scope="request"class="abc.Test"/>
<%
String name=request.getParameter("name");
if(name!=null) {
boolean b=test.ch(name);
if(b==true){
out.println("该用户名已被注册,请换个名");
}
else{
%>
<jsp:forward page="registry2.jsp"/>
<%
}
}
%>
</FORM>
</BODY>
</HTML>registry3.jsp
<%@ page import="java.sql.*" %>
<%@ page contentType="text/html;charset=GB2312" %>
<html>
<head>
<title>registry3</title>
</head>
<body>
<%
out.println("注册成功");
%>
</body>
</html>现在的问题是我一运行registry1.jsp就会跳到registry3.jsp,registry2.jsp根本就没显示,请大家再帮帮我。高分感谢。
按你方法改了,还是报错,错误如下:type Exception reportmessage description The server encountered an internal error () that prevented it from fulfilling this request.exception org.apache.jasper.JasperException
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:367)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:552)
org.apache.jsp.registry1_jsp._jspService(registry1_jsp.java:75)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
tw.com.javaworld.CH11.HelloFilter.doFilter(Unknown Source)
root cause java.lang.NullPointerException
org.apache.jsp.registry2_jsp._jspService(registry2_jsp.java:57)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:552)
org.apache.jsp.registry1_jsp._jspService(registry1_jsp.java:75)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:136)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:294)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
tw.com.javaworld.CH11.HelloFilter.doFilter(Unknown Source)
note The full stack trace of the root cause is available in the Tomcat logs.
boolean b=test.ch(name);
if(b){
out.println("该用户名已被注册,请换个名");
}
这条语句中有错吧。应该是test(user,password)吧!再看看!
registry1.jsp 如下:
<HTML>
<HEAD>
<TITLE>registry1</TITLE>
</HEAD>
<BODY>
<FORM METHOD=POST ACTION="registry1.jsp">
姓名:<input name="name" type="text">
<input type="submit" value="提交">
<jsp:useBeanid="test"scope="request"class="abc.Test"/>
<%
String name=request.getParameter("name");
if(name!=null) {
boolean b=test.ch(name);
if(b==true){
out.println("该用户名已被注册,请换个名");
}
else{
%>
<jsp:forward page="registry2.jsp">
<jsp:param name="username" value="<%=name%>"/>
</jsp:forward>
<%
}
}
%>
</FORM>
</BODY>
</HTML>
<%@ page import="java.sql.*" %>
<%@ page contentType="text/html;charset=GB2312" %>
<html>
<head>
<title>registry2</title>
</head>
<body>
<%
String user_password = request.getParameter("user_password");
String name = request.getParameter("username");
if(user_password !=null){
String confim = request.getParameter("confim");
if(user_password.equals(confim)) {
%>
<jsp:useBean id = "test" scope = "request" class = "abc.Test"/>
<%
test.save(name,user_password);
%>
<jsp:forward page="registry3.jsp"/>
<%
}
else out.println("输入密码和确认密码不同,重新输入.");
}
%><form method=post action="registry2.jsp">
<input name="user_password" type="password">
<input name="confim" type="password">
<input type="hidden" name="username" value="<%=name%>">
<input type="submit" value="提交">
</form>
</body>
</html>前提是你的bean正确的
tutor666(小虫)
tutor666(小虫)
请你到http://community.csdn.net/Expert/topic/3468/3468960.xml?temp=.9865229这里来,还有你QQ没加我。谢谢了。