Calendar date = new Calendar();
date.setTime(rs.getDate("rq"));
int year = date.get(Calendar.YEAR);
int month = date.get(Calendar.MONTH);
int day = date.get(Calendar.DATE);
date.setTime(rs.getDate("rq"));
int year = date.get(Calendar.YEAR);
int month = date.get(Calendar.MONTH);
int day = date.get(Calendar.DATE);
解决方案 »
- apache-tomcat-6.0.16
- 一道面试题:jsp中,如何获得服务器中session的总数
- 连接MySQL的怪问题
- 如何设置tomcat5.5.9显示控制台
- session不能传递request对象吗?
- 帮忙 为什么老提示javabean类找不到?
- a为int型,且a=2,我该如何判断a是否等于2,if (a=2) {....} ,但此句在执行时总是出错,我该如何写这个判断。
- 我不吝啬:如何设置才能使 JBuilder 的源代码一直可以保持中文,而不是\u1234的形式?
- 数据库中的中文在浏览器中显示为乱码,请问该如何解决!
- 请问在win2000下用iis+jdk1.31+Tomcat3.2如何配置?我按照以前的帖子怎么也没成功,求教!
- 来讨论吧!!!关于servlet的生成期问题,烦啊!!!!请看以下程序!!!!!!!!!!!!!!!!!!!!!!!
- 如何在iframe里面重新提交主页面的button?
String theDay = re.getString("rq");
StringTokenizer theTokenizer = new StringTokenizer(theDay,"//");
String month = theTokenizer.nextToken();
String day= theTokenizer.nextToken();
String year = theTokenizer.nextToken();
year = year.SubString(0,4); //去掉后面的小时数
%>
<input name=year type=text title="输入时请输入‘YYYY’" value="<%=year%>" size="4">年
<input name=month type=text title="输入时请输入‘MM’" value="<%=month%>" size="2">月
<input name=day type=text title="输入时请输入‘DD’" value="<%=day%>" size="2">日
Tasia(这里是CSDN吗?)
D:\Tomcat\work\Catalina\localhost\test\org\apache\jsp\admin\oildchange_jsp.java:197: java.util.Calendar is abstract; cannot be instantiated
Calendar date = new Calendar();
laoxing521(想做程序员的农民)
javax.servlet.ServletException: ?????
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:825)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:758)
org.apache.jsp.admin.oildchange_jsp._jspService(oildchange_jsp.java:768)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:810)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:298)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:810)
filters.SetCharacterEncodingFilter.doFilter(SetCharacterEncodingFilter.java:122)
Calendar date = Calendar.getInstance()
问题解决了,非常感谢各位。
D:\Tomcat\work\Catalina\localhost\test\org\apache\jsp\admin\oildchange_jsp.java:198: ';' expected
date.setTime(rs.getDate("rq"));
^
1 error
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:83)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:315)
org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:406)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:463)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:442)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:430)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:511)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:274)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:810)
filters.SetCharacterEncodingFilter.doFilter(SetCharacterEncodingFilter.java:122)
特定于“MM/DD/YYYY”的形式,如果日期的形式改一下,就又要修改代码了
并且,这个方法一点都不灵活无奈,对JAVA中日期,时间的操作不太熟,就只能用字符串分割的获取各对应的东东了