SQL Server怎么不支持JDBC的方法，像previous()，last()，求可操作ResultSet的方法！

我已经设置  TYPE_SCROLL_SENSITIVE 了 ！！！代码如下 ：Connection conn =bean.getConn();CallableStatement cstmt = conn.prepareCall(procname,ResultSet.TYPE_SCROLL_SENSITIVE,ResultSet.CONCUR_READ_ONLY);//CallableStatement cstmt = bean.getCstmt(procname);//设置参数   
cstmt.setString(1,begintm);
cstmt.setInt(2, project_int);//执行查询返回记录集
ResultSet rs=cstmt.executeQuery();
rs.next();
int k = rs.getRow();
rs.next();
int kk = rs.getRow();out.print("第一行：" + k);out.print("第二行：" + kk);rs.beforFirst();
可是就是出错：
javax.servlet.ServletException: Result set type is TYPE_FORWARD_ONLY
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:825)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:758)
org.apache.jsp.csrperformance.csr_005fresult_jsp._jspService(csr_005fresult_jsp.java:228)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:94)
javax.servlet.http.HttpServlet.service(HttpServlet.java:810)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:324)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:810)