请帮忙看下,帮忙看下ATION注入后,页面跳不进ACTION,我根据参考了网上的一些建议还是不行

Question

本帖最后由 FaDufendouLiang 于 2012-12-04 10:14:20 编辑

Answer 1

JSP
<form action="<%=path %>/regest" method="post">
WEB配置文件<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<!-- struts2 滤镜配置  -->
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!--Spring ApplicationContext载入 ，必须-->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
   classpath:*/springApplicationContext.xml
        </param-value>
</context-param>

Answer 2

<action name="regest" class="regestAction" method="save"  >写错了Messages: regestAction 
Unable to instantiate Action, regestAction, defined for 'regest' in namespace '/'regestAction 不可以 实例 化 regestAction <action name="regest" class="com.xx.regestAction" method="save"  >你的包路径去那里了

Answer 3

我都是这样注入的
<bean id="fpFindPersonMessageAction" class="net.aykj.findPerson.action.FindPersonMessageAction" scope="prototype" />
<bean id="fpIndexFindPersonMessageAction" class="net.aykj.findPerson.action.IndexFindPersonMessageAction"  scope="prototype"/>
<bean id="fpFindPersonMessageService" class="net.aykj.findPerson.serviceimpl.FindPersonMessageServiceImpl" />
<bean id="fpFindPersonMessageDAO" class="net.aykj.findPerson.daoimpl.FindPersonMessageDAOImpl" />用的是半自动的那种，还用了注解